stoi causes out of range error

问题

I have this code which gives me the error terminating with uncaught exception of type std::out_of_range: stoi: out of range

which I have identified as being caused by the line long ascii = std::stoi(temp_string);

what about the way i'm using stoi is causing that and how can I fix it?

std::string encode(std::string message){
std::string num_value;
long cipher;
if(message.length() < 20){
  for(int i = 0; i < message.length(); ++i){
    int temp = (char) message.at(i); 
    num_value += std::to_string(temp); 
  }
  return num_value;
}
else{
    int count = 0;   
    std::string temp_string;
    for(int i = 0; i < message.length(); ++i){
      int temp = (int)  message.at(i);
      temp_string += std::to_string(temp);           
      count++;   
       if(count == 20){
         count = 0;
         //add cipher encrypt
         long ascii = std::stoi(temp_string);
         //cipher = pow(ascii, 10000);
         //add n to cipther encrypt
         //add cipherencrypt + n to num_value
         //reset temp_string
         temp_string += "n";

         temp_string = ""; 

      }
 }
return num_value;
}

int main(){
  std::string s = "Hello World my t's your name aaaaaaaaaaaaa?";
  std::cout<<"encoded value : "<< encode(s)<<std::endl;
}

回答1:

std::stoi returns an integer; it sounds like your number is too large for an integer. Try using std::stol instead (see here).

Also if you intend for the code to be portable (useable with different compilers/platforms), keep in mind that integers and longs have no standard size. Unless the minimum size given by the standard is enough, you may want to look at using intX_t (where X is the size you want), as given in the cstdint header.

来源：https://stackoverflow.com/questions/29931827/stoi-causes-out-of-range-error