Iterate file name with counter

问题

I'm splitting a file based on a string, and would like to have the output file names be numbered.

This is what I have so far:

outputfile = open("output.seq")   
outputfileContent = outputfile.read()
outputfileList = outputfileContent.split(">")
for count, line in enumerate(f):
    for items in outputfileList:
        seqInfoFile = open('%f.dat', 'w')
    seqInfoFile.write(str(items))

I'm not sure where to define f.

Thanks for any help!

回答1:

Assuming I haven't misunderstood you, where you have it.

outputfile = open("output.seq")   
outputfileContent = outputfile.read()
outputfileList = outputfileContent.split(">")

for count, content in enumerate(outputfileList, 1):
    with open("output_%s.dat" % count, "w") as output:
        output.write(content)

回答2:

It would seem that if you want to associate every item in the output file list with a file titled as its index, you should do something like this:

for i in range(len(outputfileList)):
    seqInfoFile = open(str(i) + '.dat', 'w')
    seqInfoFile.write(str(outputfileList[i]))

It's not quite as elegant as an iterator, but the other option is to determine the number by making a call to outputfileList.index(items) each time.

回答3:

Open output.seq, write its first line (splitted at >) into the file 1.dat, the second one to 2.dat and so on:

with open("output.seq") as fi:
    for count, line in enumerate(fi, 1):
        with open('{0}.dat'.format(count), 'w') as fo:
            fo.writelines(line.split('>'))

来源：https://stackoverflow.com/questions/11651360/iterate-file-name-with-counter

标签

python

counter