问题
I am searching a way to execute asynchronously two functions in go which returns different results and errors, wait for them to finish and print both results. Also if one of function returned error I do not want to wait for another function, and just print the error. For example, I have this functions:
func methodInt(error bool) (int, error) {
<-time.NewTimer(time.Millisecond * 100).C
if error {
return 0, errors.New("Some error")
} else {
return 1, nil
}
}
func methodString(error bool) (string, error) {
<-time.NewTimer(time.Millisecond * 120).C
if error {
return "", errors.New("Some error")
} else {
return "Some result", nil
}
}
Here https://play.golang.org/p/-8StYapmlg is how I implemented it, but it has too much code I think. It can be simplified by using interface{} but I don't want to go this way. I want something simpler as, for example, can be implemented in C# with async/await. Probably there is some library that simplifies such operation.
UPDATE: Thank for your responses! It is awesome how fast I got help! I like the usage of WaitGroup. It obviously makes the code more robust to changes, so I easily can add another async method without changing exact count of methods in the end. However, there is still so much code in comparison to same in C#. I know that in go I don't need to explicitly mark methods as async, making them actually to return tasks, but methods call looks much more simple, for example, consider this link actually catching exception is also needed By the way, I found that in my task I actually don't need to know returning type of the functions I want to run async because it will be anyway marshaled to json, and now I just call multiple services in the endpoint layer of go-kit.
回答1:
You should create two channels for errors and results, then first read errors if no erorrs then read the results, this sample should works for your use case:
package main
import (
"errors"
"sync"
)
func test(i int) (int, error) {
if i > 2 {
return 0, errors.New("test error")
}
return i + 5, nil
}
func test2(i int) (int, error) {
if i > 3 {
return 0, errors.New("test2 error")
}
return i + 7, nil
}
func main() {
results := make(chan int, 2)
errors := make(chan error, 2)
var wg sync.WaitGroup
wg.Add(1)
go func() {
defer wg.Done()
result, err := test(3)
if err != nil {
errors <- err
return
}
results <- result
}()
wg.Add(1)
go func() {
defer wg.Done()
result, err := test2(3)
if err != nil {
errors <- err
return
}
results <- result
}()
// here we wait in other goroutine to all jobs done and close the channels
go func() {
wg.Wait()
close(results)
close(errors)
}()
for err := range errors {
// here error happend u could exit your caller function
println(err.Error())
return
}
for res := range results {
println("--------- ", res, " ------------")
}
}
回答2:
I think here sync.WaitGroup can be used. It can waits for different and dynamic number of goroutines.
回答3:
I have created a smaller, self-contained example of how you can have two go routines run asynchronously and wait for both to finish or quit the program if an error occurs (see below for an explanation):
package main
import (
"errors"
"fmt"
"math/rand"
"time"
)
func main() {
rand.Seed(time.Now().UnixNano())
// buffer the channel so the async go routines can exit right after sending
// their error
status := make(chan error, 2)
go func(c chan<- error) {
if rand.Intn(2) == 0 {
c <- errors.New("func 1 error")
} else {
fmt.Println("func 1 done")
c <- nil
}
}(status)
go func(c chan<- error) {
if rand.Intn(2) == 0 {
c <- errors.New("func 2 error")
} else {
fmt.Println("func 2 done")
c <- nil
}
}(status)
for i := 0; i < 2; i++ {
if err := <-status; err != nil {
fmt.Println("error encountered:", err)
break
}
}
}
What I do is create a channel that is used for synchronization of the two go routines. Writing to and reading from it blocks. The channel is used to pass the error value around, or nil if the function succeeds.
At the end I read one value per async go routine from the channel. This blocks until a value is received. If an error occurs, I exit the loop, thus quitting the program.
The functions either succeed or fail randomly.
I hope this gets you going on how to coordinate go routines, if not, let me know in the comments.
Note that if you run this in the Go Playground, the rand.Seed will do nothing, the playground always has the same "random" numbers, so the behavior will not change.
来源:https://stackoverflow.com/questions/46906647/wait-result-of-multiple-goroutines