问题
I don't understand why
SELECT UUID();
Returns something like:
3f06af63-a93c-11e4-9797-00505690773f
But if I insert it into a binary(16) field (the UUID() function) with for instance a BEFORE INSERT trigger and run a select, it returns something like:
0782ef48-a439-11
Note that these two UUIDs are not the same data.
I realize binary and an UUID string doesn't look identical, but shouldn't the selected data at least be just as long? Otherwise how can it possibly be equally likely to be unique?
Is it better to store it as char(36)? I just need it to be unique to prevent duplicate inserts. It is never selected or used for joins.
EDIT:
before trigger would be like:
BEGIN
if NEW.UUID IS NULL THEN
NEW.UUID = UUID();
END IF
END
回答1:
So, as a response to comments. The correct way of storing a 36-char UUID as binary(16) is to perform the insert in a manner like:
INSERT INTO sometable (UUID) VALUES
(UNHEX(REPLACE("3f06af63-a93c-11e4-9797-00505690773f", "-","")))
UNHEX
because an UUID is already a hexed value. We trim (REPLACE
) the dashes in the statement to bring the length down to 32 ASCII characters (our 16 bytes represented as HEX
). You can do this at any point before storing it, obviously, so it doesn't have to be handled by the database.
You may retrieve the UUID like this:
SELECT HEX(UUID) FROM sometable;
Just in case someone comes across this thread and is unsure how this works.
And remember: If you're selecting a row using the UUID, use UNHEX()
on the condition:
SELECT * FROM sometable WHERE UUID = UNHEX('3f06af63a93c11e4979700505690773f');
And not HEX()
on the column:
SELECT * FROM sometable WHERE HEX(UUID) = '3f06af63a93c11e4979700505690773f';
The second solution, while it works, requires that MySQL HEX
es all UUIDs before it can determine which rows match. It's very inefficient.
Edit: If you're using MySQL 8 you should have a look at the UUID functions as mentioned in SlyDave's answer. This answer is still correct, but it doesn't optimise the UUID indexes which can be done natively using those functions.
回答2:
As of MySQL 8 you can use two new UUID functions:
BIN_TO_UUID
SELECT BIN_TO_UUID(uuid, true) AS uuid FROM foo; -- 3f06af63-a93c-11e4-9797-00505690773f
UUID_TO_BIN
INSERT INTO foo (uuid) VALUES (UUID_TO_BIN('3f06af63-a93c-11e4-9797-00505690773f', true));
This method also supports rearranging the time component of the uuid to enhance indexing performance (by ordering it chronologically), simply set the second argument to true - this only works for UUID1.
If you are using the true
on UUID_TO_BIN
flag for indexing performance (recommended), you must also set it on BIN_TO_UUID
otherwise it won't convert back properly.
See the documentation for further details.
- https://dev.mysql.com/doc/refman/8.0/en/miscellaneous-functions.html#function_uuid-to-bin
- http://mysqlserverteam.com/mysql-8-0-uuid-support/
回答3:
Polyfill for BIN_TO_UUID and UUID_TO_BIN for MySQL 5 with the swap_flag parameter.
DELIMITER $$
CREATE FUNCTION BIN_TO_UUID(b BINARY(16), f BOOLEAN)
RETURNS CHAR(36)
DETERMINISTIC
BEGIN
DECLARE hexStr CHAR(32);
SET hexStr = HEX(b);
RETURN LOWER(CONCAT(
IF(f,SUBSTR(hexStr, 9, 8),SUBSTR(hexStr, 1, 8)), '-',
IF(f,SUBSTR(hexStr, 5, 4),SUBSTR(hexStr, 9, 4)), '-',
IF(f,SUBSTR(hexStr, 1, 4),SUBSTR(hexStr, 13, 4)), '-',
SUBSTR(hexStr, 17, 4), '-',
SUBSTR(hexStr, 21)
));
END$$
CREATE FUNCTION UUID_TO_BIN(uuid CHAR(36), f BOOLEAN)
RETURNS BINARY(16)
DETERMINISTIC
BEGIN
RETURN UNHEX(CONCAT(
IF(f,SUBSTRING(uuid, 15, 4),SUBSTRING(uuid, 1, 8)),
SUBSTRING(uuid, 10, 4),
IF(f,SUBSTRING(uuid, 1, 8),SUBSTRING(uuid, 15, 4)),
SUBSTRING(uuid, 20, 4),
SUBSTRING(uuid, 25))
);
END$$
DELIMITER ;
SET @uuid = '6ccd780c-baba-1026-9564-5b8c656024db';
-- SELECTS with the actual values followed by expected value:
SELECT HEX(UUID_TO_BIN(@uuid, 0)), '6CCD780CBABA102695645B8C656024DB';
SELECT HEX(UUID_TO_BIN(@uuid, 1)), '1026BABA6CCD780C95645B8C656024DB';
SELECT BIN_TO_UUID(UUID_TO_BIN(@uuid,0),0), '6ccd780c-baba-1026-9564-5b8c656024db';
SELECT BIN_TO_UUID(UUID_TO_BIN(@uuid,1),1), '6ccd780c-baba-1026-9564-5b8c656024db';
Included are the SELECT samples from https://dev.mysql.com/doc/refman/8.0/en/miscellaneous-functions.html#function_uuid-to-bin that demonstrate that the above code returns the exact same results as the 8.0 function. These functions are considered DETERMINISTIC as they always produce the same output for a given input. See https://dev.mysql.com/doc/refman/8.0/en/create-procedure.html
回答4:
I am using MariaDB so BIN_TO_UUID
functions family do not exist. I managed to get the corresponding values anyway.
bin -> hex
Here, uuid
is the binary(16) value of an uuid; you'll use the value below to SELECT a readable version of it.
LOWER(CONCAT(
SUBSTR(HEX(uuid), 1, 8), '-',
SUBSTR(HEX(uuid), 9, 4), '-',
SUBSTR(HEX(uuid), 13, 4), '-',
SUBSTR(HEX(uuid), 17, 4), '-',
SUBSTR(HEX(uuid), 21)
))
hex -> bin
Here, cc6e6d97-5501-11e7-b2cb-ceedca613421
is a readable version of an UUID, and you'll use the value below in a WHERE clause to seek for it.
UNHEX(REPLACE('cc6e6d97-5501-11e7-b2cb-ceedca613421', '-', ''))
Cheers
回答5:
The other answers are correct. The UUID()
function returns a 36 character string and that needs to be converted using the shown functions (UNHEX()
or, on newer platforms, UUID_TO_BIN()
).
However, if you use your own software to create your UUIDs, then you can use the Hexadecimal Literal notation instead.
So I would use the following with the MySQL UUID()
function:
INSERT INTO sometable (id) VALUES (UNHEX(REPLACE(UUID(), '-', ''))); -- all versions
INSERT INTO sometable (id) VALUES (UUID_TO_BIN(UUID()); -- since v8.0
But use this in case I generate my own UUIDs;
INSERT INTO sometable (id) VALUES 0x3f06af63a93c11e4979700505690773f;
Similarly, you can use Hexadecimal Literals in your WHERE
clauses:
SELECT * FROM sometable WHERE id = 0x3f06af63a93c11e4979700505690773f;
This will be faster if you do not have to convert your data to a UUID string each time.
Note: the 'x'
in '0xaBc
is case sensitive. The hexadecimal digits are not, however.
来源:https://stackoverflow.com/questions/28251144/inserting-and-selecting-uuids-as-binary16