LEFT JOIN only first row

Question

I read many threads about getting only the first row of a left join, but, for some reason, this does not work for me.

Here is my structure (simplified of course)

Feeds

id |  title | content
----------------------
1  | Feed 1 | ...

Artists

artist_id | artist_name
-----------------------
1         | Artist 1
2         | Artist 2

feeds_artists

rel_id | artist_id | feed_id
----------------------------
1      |     1     |    1 
2      |     2     |    1 
...

Now i want to get the articles and join only the first Artist and I thought of something like this:

SELECT *
    FROM feeds 
    LEFT JOIN feeds_artists ON wp_feeds.id = (
        SELECT feeds_artists.feed_id FROM feeds_artists
        WHERE feeds_artists.feed_id = feeds.id 
    LIMIT 1
    )
WHERE feeds.id = '13815'

just to get only the first row of the feeds_artists, but already this does not work.

I can not use TOP because of my database and I can't group the results by feeds_artists.artist_id as i need to sort them by date (I got results by grouping them this way, but the results where not the newest)

Tried something with OUTER APPLY as well - no success as well. To be honest i can not really imagine whats going on in those rows - probably the biggest reason why i cant get this to work.

SOLUTION:

SELECT *
FROM feeds f
LEFT JOIN artists a ON a.artist_id = (
    SELECT artist_id
    FROM feeds_artists fa 
    WHERE fa.feed_id = f.id
    LIMIT 1
)
WHERE f.id = '13815'

Answer 1

If you can assume that artist IDs increment over time, then the MIN(artist_id) will be the earliest.

So try something like this (untested...)

SELECT *
  FROM feeds f
  LEFT JOIN artists a ON a.artist_id = (
    SELECT
      MIN(fa.artist_id) a_id
    FROM feeds_artists fa 
    WHERE fa.feed_id = f.feed_id
  ) a

Answer 2

Version without subselect:

   SELECT f.title,
          f.content,
          MIN(a.artist_name) artist_name
     FROM feeds f
LEFT JOIN feeds_artists fa ON fa.feed_id = f.id
LEFT JOIN artists a ON fa.artist_id = a.artist_id
 GROUP BY f.id

Answer 3

@Matt Dodges answer put me on the right track. Thanks again for all the answers, which helped a lot of guys in the mean time. Got it working like this:

SELECT *
FROM feeds f
LEFT JOIN artists a ON a.artist_id = (
    SELECT artist_id
    FROM feeds_artists fa 
    WHERE fa.feed_id = f.id
    LIMIT 1
)
WHERE f.id = '13815'

Answer 4

I've used something else (I think better...) and want to share it:

I created a VIEW that has a "group" clause

CREATE VIEW vCountries AS SELECT * PROVINCES GROUP BY country_code

SELECT * FROM client INNER JOIN vCountries on client_province = province_id

I want to say yet, that I think that we need to do this solution BECAUSE WE DID SOMETHING WRONG IN THE ANALYSIS... at least in my case... but sometimes it's cheaper to do this that to redesign everything...

I hope it helps!

Answer 5

I want to give a more generalized answer. One that will handle any case when you want to select only the first item in a LEFT JOIN.

You can use a subquery that GROUP_CONCATS what you want (sorted, too!), then just split the GROUP_CONCAT'd result and take only its first item, like so...

LEFT JOIN Person ON Person.id = (
    SELECT SUBSTRING_INDEX(
        GROUP_CONCAT(FirstName ORDER BY FirstName DESC SEPARATOR "_" ), '_', 1)
    ) FROM Person
);

Since we have DESC as our ORDER BY option, this will return a Person id for someone like "Zack". If we wanted someone with the name like "Andy", we would change ORDER BY FirstName DESC to ORDER BY FirstName ASC.

This is nimble, as this places the power of ordering totally within your hands. But, after much testing, it will not scale well in a situation with lots of users and lots of data.

It is, however, useful in running data-intensive reports for admin.