typescript: How to get objects with the same property values but different keys from 2 different sets of Objects

问题

I have to sets of Json got from the form the state data

objetSet1:
  {id: 12, name: 'Foo Bar', email: 'foo@bar.com'},
  {id: 23, name: 'Bar Foo', email: 'bar@foo.com'},
  {id: 61, name: 'Barbell', email: 'barbell@mail.com'},
  {id: 45, name: 'Joe Ocean', email: 'joe@ocean.com'}

objectSet2:
  {ObjectId:15, name: 'someone', email: 'someone@mail.com'},
  {ObjectId: 23, name: 'sometwo', email: 'sometwo@mail.com'},
  {ObjectId: 72, name: 'seven ', email: 'seven@mail.com'},
  {ObjectId: 23, name: 'five ', email: 'five@mail.com'}

I was actually looking for a way to get this expression to be dynamic

objectSet2 = objectSet2.filter(object => object.ObjectId === '23')

instead of 23 static value, the value from objectSet1 corresponding

the result should contain Item with ids present on the first object set

expected output:

objectSet2:
      {ObjectId: 23, name: 'sometwo', email: 'sometwo@mail.com'},
      {ObjectId: 23, name: 'five ', email: 'five@mail.com'}

回答1:

Yoy were close, just needed to add a new filter like this:

objetSet1 = [{id: 12, name: 'Foo Bar', email: 'foo@bar.com'},
  {id: 23, name: 'Bar Foo', email: 'bar@foo.com'},
  {id: 61, name: 'Barbell', email: 'barbell@mail.com'},
  {id: 45, name: 'Joe Ocean', email: 'joe@ocean.com'}];
  
  objectSet2 = [{ObjectId:15, name: 'someone', email: 'someone@mail.com'},
  {ObjectId: 23, name: 'sometwo', email: 'sometwo@mail.com'},
  {ObjectId: 72, name: 'seven ', email: 'seven@mail.com'},
  {ObjectId: 23, name: 'five ', email: 'five@mail.com'}];
  
 var result = objectSet2.filter((obj2)=>objetSet1.filter((obj1)=>obj1.id==obj2.ObjectId).length>0)
 
 console.log(result);

Please note obj1.id==obj2.ObjectId comparison. It's returning true when the count of positive matches on the inner filter is greater than zero. Then this is the answer for the outer filter.

回答2:

You could create a set of ids from the first array:

  const ids = new Set(objectSet1.map(object => object.id));

Then you can check wether objects from the second array are in that set

  ids.has(object.ObjectId)

回答3:

This combines Jonas Wilms and Ictus' answers in a way that I think is slightly clearer, and I've commented the code for future readers to know what's being done.

// Define Yoann Eddy's original two sets of objects, but as Arrays
let objectSet1 = [
  {id: 12, name: 'Foo Bar', email: 'foo@bar.com'},
  {id: 23, name: 'Bar Foo', email: 'bar@foo.com'},
  {id: 61, name: 'Barbell', email: 'barbell@mail.com'},
  {id: 45, name: 'Joe Ocean', email: 'joe@ocean.com'}
];

let objectSet2 = [
  {ObjectId:15, name: 'someone', email: 'someone@mail.com'},
  {ObjectId: 23, name: 'sometwo', email: 'sometwo@mail.com'},
  {ObjectId: 72, name: 'seven ', email: 'seven@mail.com'},
  {ObjectId: 23, name: 'five ', email: 'five@mail.com'}
];

// Get just the ID numbers from the first set
let ids = new Set(objectSet1.map(o => o.id));

// Filter the second set, keeping only the objects that have
// an object.ObjectId that is in the first set of IDs
let result = objectSet2.filter(o => ids.has(o.ObjectId));

console.log(result);

Ictus's all-in-one line does the job, but will be harder to maintain simply because it's harder to understand by a colleague (or your future self)

来源：https://stackoverflow.com/questions/60439450/typescript-how-to-get-objects-with-the-same-property-values-but-different-keys