Django dump data for a single model?

蹲街弑〆低调 提交于 2019-11-27 16:49:08
simplyharsh

As of version 1.1 and greater, the Django dumpdata management command allows you to dump data from individual tables:

./manage.py dumpdata myapp1 myapp2.my_model

You can also separate multiple apps and models on the command line. Here's the canonical definition:

django-admin dumpdata [app_label[.ModelName] [app_label[.ModelName] ...]]
dar

As noted, you can't do this through a manage.py command in Django 1.0. However you could use a script to export the JSON file, and load it using loaddata:

from django.core import serializers
from myproject.myapp import models
data = serializers.serialize("json", models.MyModel.objects.all())
out = open("mymodel.json", "w")
out.write(data)
out.close()
Harold

I think you had the solution in your question. You can dump an individual model like this:

./manage.py dumpdata myapp.my_model

Take all data into json format from django model.

Syntax:

python manage.py dumpdata app_name.model_name

For example dumping data from group_permission model which reside in default auth app in django.

python manage.py dumpdata auth.group_permission

For output take a look on console.

For success I had to say it twice, and specify the model two times, like:

./manage.py dumpdata myapp2.my_model myapp2.my_model

If I only said

./manage.py dumpdata myapp2 myapp2.my_model

I got flooded with all the models in myapp2, despite the fact that I specified my_model.

As a workaround you could make another app and copy the model but point it to the existing table with the db_table meta option. Then you could just dump the models you copied into the new app. You existing app wouldn't be affected.

I've created a management command the generate a fixture on a per model basis. Fixtures can be generated by running:

./manage generate_fixtures app.model.MyModel --file=dump/MyModel.json

code at: https://gist.github.com/2394883

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