OpenCV 金字塔图像缩放

守給你的承諾、 提交于 2020-03-06 11:46:04

 

 

// image_pyramid.cpp : 定义控制台应用程序的入口点。
//

#include "stdafx.h"
#include <string>
#include <iostream>
using namespace std;

#include "opencv2/imgproc/imgproc.hpp"
#include "opencv2/highgui/highgui.hpp"
#include <math.h>
#include <stdlib.h>
#include <stdio.h>



#pragma comment(lib,"opencv_core2410d.lib")  
#pragma comment(lib,"opencv_highgui2410d.lib")  
#pragma comment(lib,"opencv_imgproc2410d.lib")  
  

using namespace cv;

/// 全局变量
Mat src, dst, tmp;
char* window_name = "Pyramids Demo";


/**
 * @函数 main
 */
int main( int argc, char** argv )
{
  /// 指示说明
  printf( "\n Zoom In-Out demo  \n " );
  printf( "------------------ \n" );
  printf( " * [u] -> Zoom in  \n" );
  printf( " * [d] -> Zoom out \n" );
  printf( " * [ESC] -> Close program \n \n" );

  /// 测试图像 - 尺寸必须能被 2^{n} 整除
  string image_name;
  cout<<"input image name:"<<endl;
  cin>>image_name;

  src = imread( image_name);
  if( !src.data )
    { printf(" No data! -- Exiting the program \n");
      return -1; }

  tmp = src;
  dst = tmp;

  /// 创建显示窗口
  namedWindow( window_name, CV_WINDOW_AUTOSIZE );
  imshow( window_name, dst );

  /// 循环
  while( true )
  {
    int c;
    c = waitKey(10);

    if( (char)c == 27 )
      { break; }
    if( (char)c == 'u' )
      { pyrUp( tmp, dst, Size( tmp.cols*2, tmp.rows*2 ) );
        printf( "** Zoom In: Image x 2 \n" );
      }
    else if( (char)c == 'd' )
     { pyrDown( tmp, dst, Size( tmp.cols/2, tmp.rows/2 ) );
       printf( "** Zoom Out: Image / 2 \n" );
     }

    imshow( window_name, dst );
    tmp = dst;
  }
  return 0;
}

//缩小,再放大就模糊了,什么情况?


 

 

 

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