.plot() command does not display anything

问题

I have this code based on this question, just a different point Extract constrained polygon using OSMnx

I am trying to plot the block in which the point is located but it does nothing, it just prints "Done" but I cannot see any image

import osmnx as ox
import geopandas as gpd
import shapely

point = (50.090464, 14.400070)

streets_graph = ox.graph_from_point(point, distance=500, network_type='drive')
streets_graph = ox.project_graph(streets_graph)

streets = ox.save_load.graph_to_gdfs(streets_graph, nodes=False, edges=True,
                                     node_geometry=False, fill_edge_geometry=True)

point = streets.unary_union.centroid

polygons = shapely.ops.polygonize(streets.geometry)
polygons = gpd.GeoSeries(polygons)

target = polygons.loc[polygons.contains(point)]

target_streets = streets.loc[streets.intersection(target.iloc[0]).type == 'MultiLineString']

ax = target_streets.plot()
gpd.GeoSeries([point]).plot(ax=ax, color='r')

print("Done")

I do not think this may help but I am using Visual Studio Code

Thank you very much

回答1:

Since my comment answered your question, I will summarize it here for other people:

When using plotting library dependent on matplotlib, like geopandas or seaborn, you will need to import matplotlib in order to show the plot. The way matplotlib is imported will depend on whether you are using Jupyter or simple scripting (.py) files.

For Jupyter you need to import it like this: