问题
My Problem
Consider a set of data with two intervals. For instance, consider a student schedule of classes. Each record has a begin and end date, and each class has a period start time and a period end time. But this schedule is not 'normalized' in the sense that some records overlap. So if you search for records encompassing a given date and period for a student, you might get multiple matches.
Here's a contrived example. I represent the dates as integers to simplify the problem:
declare @schedule table (
student char(3),
fromDate int,
toDate int,
fromPeriod int,
toPeriod int
)
insert @schedule values
('amy', 1, 7, 7, 9),
('amy', 3, 9, 5, 8),
('amy', 10, 12, 1, 3),
('ted', 1, 5, 11, 14),
('ted', 7, 11, 13, 16);
Amy's date and period ranges either overlap or are adjacent. If I queried for 'date 5 period 7', I would get two matches. I need these reworked so that they represent the same 'area' but no longer overlap.
Ted's periods overlap but his dates do not. This means there's no real overlap, so no need to re-work anything.
My Research
I've read many posts and some articles on working overlapping intervals. Namely:
- Merge overlapping date intervals
- Flattening intersecting timespans
- Condense Time Periods with SQL
- SQL Server - cumulative sum on overlapping data - getting date that sum reaches a given value
- Flatten/merge overlapping time intervals
- SQL Server separate overlapping dates
I've implemented one from Itzik from a blog entitled 'solutions-packing-date-and-time-intervals-puzzle' that has worked great for one particular project. I don't think it's a stable link, but I've found a copy of it here.
But I'm having difficulty extending the knowledge in those resources to my problem at hand. It might be my limitation. I have trouble following them. I've studied Itzik's solution and have come to understand a lot of it, but I do recall there's one piece I just couldn't understand. Or it might be that those solutions only work with singular ranges.
My Attempt
I resolved this question by treating the ranges as literal rectangle objects. It works. I've even made a version of it somewhat performant in my own application. So I'll post it as a solution in case it is of use to anyone with the same issue.
But it is so long and involved and there are enough quirks to it (e.g. buffering lines, looping shapes, working with float values, rounding issues) that I can't help but think that there's a much better way. Can the concepts of my listed resources be extended to dual ranges? Or do some SRID's allow cutting rectangles with zero-length lines?
Expected Results:
There is no one answer to this problem, because you can aggregate ranges and deconstruct them in different ways. But to minimize the number of resulting rectangles, there are really only two acceptable answers. Visually, with dates on the X axis and periods on the Y axis, overlapping ranges can start out like this:
+------------+
| |
| +------------+
| |||||||| | <- 2 overlapping rectangles
+----| |
| |
+------------+
We can rework it this way:
+---+ +-----+
| | | |
| | | | +---+ <- 3 non-overlapping
| | | | | | vertically cut rectangles
+---| | | | |
| | | |
+-----+ +---+
Or this way:
+-----------+
+-----------+
+-----------------+ <- 3 non-overlapping
+-----------------+ horizontally cut rectangles
+-----------+
+-----------+
Going with vertical cuts, the results would look like this:
+-------------------------------------------+
|student|fromDate|toDate|fromPeriod|toPeriod|
|-------------------------------------------|
|amy |1 |2 |7 |9 |
|amy |3 |7 |5 |9 |
|amy |8 |9 |5 |8 |
|amy |10 |12 |1 |3 |
|ted |1 |5 |11 |14 |
|ted |7 |11 |13 |16 |
+-------------------------------------------+
Going with horizontal cuts, the results would look like this:
+-------------------------------------------+
|student|fromDate|toDate|fromPeriod|toPeriod|
|-------------------------------------------|
|amy |1 |7 |9 |9 |
|amy |1 |9 |7 |8 |
|amy |3 |9 |5 |6 |
|amy |10 |12 |1 |3 |
|ted |1 |5 |11 |14 |
|ted |7 |11 |13 |16 |
+-------------------------------------------+
Either is acceptable. Though, to keep it deterministic and tractable, you would want to choose one strategy and stick with it.
回答1:
Numbers table:
To address the problem geometrically as I indicate in my post, you have to work with the SQL Server geometry data type. Unfortunately, to get each individual shape or point inside a geometry value, you have to call for the shape by index. A numbers table helps with this. So I do that first (swap this out for your preferred implementation).
create table #numbers (i int);
declare @i int = 1;
while @i <= 100 begin
insert #numbers values (@i);
set @i += 1;
end;
Aggregate the Ranges:
The first required task is to convert the numeric ranges to geometric rectangles. Point creates the corner points. STUnion and STEnvelope serve to turn these into a
rectangle. Also, since we desire ranges to merge together when they are integer-adjacent, we add 1 to the 'to' fields before geometric conversion.
Then the rectangles must be unioned so that there are no overlaps. This is done by UnionAggregate. The result is a geometry object of rectilinearPolygons (boxy shapes).
The geometry object can still have multiple rectillinearPolygons. So these are listed and output as individual shapes to rectilinears.
with
aggregateRectangles as (
select student,
rectilinears = geometry::UnionAggregate(rectangle)
from @schedule s
cross apply (select
minPt = geometry::Point(s.fromDate, s.fromPeriod, 0),
maxPt = geometry::Point(s.toDate + 1, s.toPeriod + 1, 0)
) extremePoints
cross apply (select rectangle = minPt.STUnion(maxPt).STEnvelope()) enveloped
group by student
)
select ar.student,
r.rectilinear,
mm.minY,
mm.maxY
into #rectilinears
from aggregateRectangles ar
join #numbers n on n.i between 1 and ar.rectilinears.STNumGeometries()
cross apply (select rectilinear = ar.rectilinears.STGeometryN(n.i)) r
cross apply (select envelope = r.rectilinear.STEnvelope()) e
cross apply (select
minY = e.envelope.STPointN(1).STY,
maxY = e.envelope.STPointN(3).STY
) mm;
SideNote - Performance Option:
I'm not implementing it here. But if you're working with big-data, and your 'rectilinears' (plural) field above is shared among many groupings (such as many students having the same schedule), then save the Well-known-text version of the rectilinear object (Just do ToString()). After this, create a second dataset with distinct rectilinears and perform the remaining geometric operations on that condensed dataset. Join it back in to the student-level later on. This has significantly improved performance in my real case.
Decompose the Ranges:
Next, those rectilinears have to be decomposed back into rectangles. Splitters are created by creating vertical lines at the x coordinates of each point. The y axis could just as easily been chosen, I just chose x for my own semantics. Both axis could also have been chosen, but this would result in more records than necessary.
Unfortunately, SQL Server does not split a shape if the splitter has zero-width (set-theoretically, that's inappropriate, but I imagine that you can't represent the result properly in WKT format). So we need to give the splitters a buffer so that they have an area. There's STBuffer, though I've had trouble with it so I just create one manually.
With this, the rectangles are split. When they're split, they still all reside in the same geometry object, so they enumerated and then inserted individually into the #rectangles table.
with
createSplitters as (
select r.student,
rectilinear = geometry::STGeomFromText(r.rectilinear.ToString(), 0),
splitters = geometry::UnionAggregate(sp.splitter)
from #rectilinears r
join #numbers n on n.i between 1 and r.rectilinear.STNumPoints()
cross apply (select
x = r.rectilinear.STPointN(n.i).STX,
buffer = 0.001
) px
cross apply (select splitter =
geometry::Point(x - buffer, minY - buffer, 0).STUnion(
geometry::Point(x + buffer, maxY + buffer, 0)
).STEnvelope()
) sp
group by r.student,
r.rectilinear.ToString()
)
select student,
rectangle = rectangles.STGeometryN(n.i)
into #rectangles
from createSplitters sp
cross apply (select
rectangles = rectilinear.STDifference(sp.splitters)
) r
join #numbers n on n.i between 1 and r.rectangles.STNumGeometries();
Parse the Ranges:
That's the crux of it. What remains is simply to extract the proper values from the rectangles to give the ranges.
To do this, we first invoke STEnvelope to ensure the rectangles are only represented by their corner points. Then we round the corner points to undo the effects of our buffer, and any issues with float representation. We also subtract 1 from the 'to' fields to undo what we did before converting to geometric points.
select student,
fromDate = round(minPt.STX,0),
toDate = round(maxPt.STX,0) - 1,
fromPeriod = round(minPt.STY,0),
toPeriod = round(maxPt.STY,0) - 1
into #normalized
from #rectangles r
cross apply (select
minPt = r.rectangle.STPointN(1),
maxPt = r.rectangle.STPointN(3)
) corners
order by student, fromDate, fromPeriod;
Optional - Visualize Before and After:
I've made it this far, so I minus well give a visual representation of the before and after results. Press the 'Spatial Results' tab in SSMS, choose 'student' as the label column, and toggle between 'unnormalized' and 'normalized' as the spatial column.
The gaps between Amy's rectangles seem like an error at first, but remember that our 'to' fields represent not just the number recorded in them, but the entire fractional part up-to but excluding the next integer number. So, for instance, a toDate of 2 is really a to date of 2.99999 etc.
select student,
unnormalized =
geometry::Point(fromDate, fromPeriod, 0).STUnion(
geometry::Point(toDate, toPeriod, 0)
).STEnvelope(),
normalized = null
from @schedule s
union all
select student,
unnormalized = null,
normalized =
geometry::Point(fromDate, fromPeriod, 0).STUnion(
geometry::Point(toDate, toPeriod, 0)
).STEnvelope()
from #normalized;
回答2:
that is a very creative solution and an interesting read!!
A rather simplistic approach:
with
a as (
select student, fromdate from @schedule union
select student, todate+1 from @schedule
),
b as (
select *,
todate = (
select min(aa.fromdate)
from a as aa
where aa.student = a.student
and aa.fromdate > a.fromdate
) - 1
from a
)
select *
from b
where exists (
select *
from @schedule as s
where s.student = b.student
and s.fromdate < b.todate
and s.todate > b.fromdate
);
来源：https://stackoverflow.com/questions/59417570/simultaneously-aggregating-overlapping-ranges-a-rectangle-problem