问题
I need to get names from destinations table for each from_destination_id and to_destination_id as fromDestinationName and toDestinationName
$bookingTransfersData = DB::table('transfers as t')
->select('t.periodStart as periodStart', 't.periodEnd as periodEnd','t.days','t.transfer_id','t.cost_round_trip',
't.cost_one_way','t.status','d.destination_id as destinationId','d.name as destinationName', 't.type',
'tf.name as officeName', 'ag.name as agencyName', 'u.name as userName', 'v.name as vehicleName')
->join('destinations as d', function ($join){
$join->on('t.from_destination_id','=','d.destination_id')
->orOn('t.to_destination_id','=','d.destination_id');
})->join('vehicles as v','t.vehicle_id','=','v.vehicle_id')
->join('transfer_offices as tf','t.office_id','=','tf.transfer_office_id')
->join('agencies as ag','t.forAgency_id','=','ag.agency_id')
->join('users as u','t.addedBy_user_id','=','u.id')
->get();
i want to get the names of each id after this results
$searchResults = $bookingTransfersData
->where('periodStart','between', $periodStart && $periodEnd)
->where('periodEnd','between', $periodStart && $periodEnd)
->where('destinationName','=',$from_destination_name && $to_destination_name)->where('type','like', $type);
like:
$fromDestinationName = $searchResults->pluck('from_destination_id','destinationName')
->where('from_destination_id','=','destinationId');
but $fromDestinationName
return an empty collection
please help :)
回答1:
I solved it by removing this join:
->join('destinations as d', function ($join){
$join->on('t.from_destination_id','=','d.destination_id')
->orOn('t.to_destination_id','=','d.destination_id');
})
and add for each destionation_id a join to retrive each name
and this will not work if I don't add for table name that i joined two times as to name it new name like
'destinations as d1'
and 'destinations as d2'
$bookingTransfersData = DB::table('transfers as t')
->select('t.periodStart as periodStart', 't.periodEnd as periodEnd','t.days','t.transfer_id','t.cost_round_trip',
't.cost_one_way','t.status','d1.destination_id as fromDestinationId','d1.name as fromDestinationName', 't.type',
't.to_destination_id','tf.name as officeName', 'ag.name as agencyName', 'u.name as userName', 'v.name as vehicleName',
't.from_destination_id', 'd2.destination_id as toDestinationId','d2.name as toDestinationName')
->join('destinations as d1','t.from_destination_id','=','d1.destination_id')
->join('destinations as d2','t.to_destination_id','=','d2.destination_id')
->join('vehicles as v','t.vehicle_id','=','v.vehicle_id')
->join('transfer_offices as tf','t.office_id','=','tf.transfer_office_id')
->join('agencies as ag','t.forAgency_id','=','ag.agency_id')
->join('users as u','t.addedBy_user_id','=','u.id')->get();
the problem solved :)
来源:https://stackoverflow.com/questions/59886057/how-to-retrieve-different-names-from-same-table-with-different-ids-on-join-larav