问题
test.sh is not replacing test.json parameter values ($input1 and $input2). result.json has same ParameterValue "$input1/solution/$input2.result"
[
{
"ParameterKey": "Project",
"ParameterValue": [ "$input1/solution/$input2.result" ]
}
]
test.sh
#!/bin/bash
input1="test1"
input2="test2"
echo $input1
echo $input2
cat test.json | jq 'map(if .ParameterKey == "Project" then . + {"ParameterValue" : "$input1/solution/$input2.result" } else . end )' > result.json
回答1:
shell variables in jq scripts should be interpolated or passed as arguments via --arg name value
:
jq --arg inp1 "$input1" --arg inp2 "$input2" \
'map(if .ParameterKey == "Project"
then . + {"ParameterValue" : ($inp1 + "/solution/" + $inp2 + ".result") }
else . end)' test.json
The output:
[
{
"ParameterKey": "Project",
"ParameterValue": "test1/solution/test2.result"
}
]
回答2:
In your jq program, you have quoted "$input1/solution/$input2.result", and therefore it is a JSON string literal, whereas you evidently want string interpolation; you also need to distinguish between the shell variables ($input1 and $input2) on the one hand, and the corresponding jq dollar-variables (which may or may not have the same name) on the other.
Since your shell variables are strings, you could pass them in using the --arg
command-line option (e.g. --arg input1 "$input1"
if you chose to name the variables in the same way).
You can read up on string interpolation in the jq manual (see https://stedolan.github.io/jq/manual, but note the links at the top for different versions of jq).
There are other ways to achieve the desired results too, but using string interpolation with same-named variables, you'd write:
"\($input1)/solution/\($input2).result"
Notice that the above string is NOT itself literally a JSON string. Only after string interpolation does it become so.
来源:https://stackoverflow.com/questions/47374719/jq-not-replacing-json-value-with-parameter