In an assignment I am currently working on we need to work with bit vectors, but I am very unsure of how to do this in Python. They should be able to be from 4 bits to 20 bits. I have never worked with bit vector before, but I guess that one would one create arrays of unsigned bytes that you manipulated using the usual AND/OR/XOR operations.
The important restriction here is: I cannot rely on any libraries other than those supplied with standard Python.
I think I know how I would do this in C using arrays of 8 bit unsigned bytes: e.g. to turn the 18th bit of a zeroed array into a one, I would do something like my_bit_array[3] &= 1<<2
But since Python is dynamically typed and does not have a built-in array type, how would I go about doing this in a pythonic way?
And is it possible (how?) to express a bit vector of size 20? I am thinking of perhaps making a 24 bit / 3 byte vector and ignoring the 4 bits.
The library BitVector is a pure-Python library for this purpose, and should suit the needs you specified.
I'm surprised that no one has mentioned int
s (or I guess long
in Python 2). int
s can be arbitrarily large, you can use bitwise operators on them, they're fast, and the code looks like bit twiddling code in C (I consider that to be an advantage).
x = 0 # empty
x |= 1<<19 # set bit 19
x &= ~(1<<19) # clear bit 19
x ^= 1<<19 # toggle bit 19
x = ~x # invert *all* bits, all the way to infinity
mask = ((1<<20)-1) # define a 20 bit wide mask
x &= mask # ensure bits 20 and higher are 0
x ^= mask # invert only bits 0 through 19
(x >> 19) & 1 # test bit 19
(x >> 16) & 0xf # get bits 16 through 20.
I've used this for bitvectors hundreds of bits long.
The bitarray module does this efficiently with booleans.
It has lists, which you can populate with bools:
[False] * 20
A bit dated but I'm going to leave another stdlib option here just for comparison sake. It is also easy to do this using the ctypes module.
For example:
And is it possible (how?) to express a bit vector of size 20 ? I am thinking of perhaps making a 24 bit / 3 byte vector and ignoring the 4 bits.
class Simple(ctypes.LittleEndianStructure):
_pack_ = 1
_fields_ = [
('one', ctypes.c_ubyte, 8),
('two', ctypes.c_ubyte, 8),
('three', ctypes.c_ubyte, 8)
]
s = Simple(0, 2, 256)
bytearray(s) # bytearray(b'\x00\x02\x00')
s = Simple(0, 2, 255)
bytearray(s) # bytearray(b'\x00\x02\xff')
class Simple(ctypes.BigEndianStructure):
_pack_ = 1
_fields_ = [
('one', ctypes.c_ubyte, 8),
('two', ctypes.c_ubyte, 8),
('three', ctypes.c_ubyte, 8)
]
s = Simple(0, 2, 256)
bytearray(s) # bytearray(b'\x00\x02\x00')
s = Simple(0, 2, 255)
bytearray(s) # bytearray(b'\x00\x02\xff')
s.two |= 3
bytearray(s) # bytearray(b'\x00\x03\xff')
or something more straight forward like this:
class bit_vector(Structure):
_fields_ = [('bits', c_uint32, 24),
('unused', c_uint32, 8),
]
bv = bit_vector()
# turn on the 18th bit -- being explicit just to demo it
bv.bits |= int('000000000000000001000000', 2)
bin(bv.bits) # 0b1000000
Use struct module.
There is also the pure-Python python-bitstring (with Python 3 support).
来源:https://stackoverflow.com/questions/2147848/how-do-i-represent-and-work-with-n-bit-vectors-in-python