问题
I have three rows with three columns in one table
id type value
1 gold 1000.00
2 silver 32.21
3 platinum 1500.00
I have a form on my page with three inputs to fill in the updated values and am using ajax to send those values to update_values.php
The code below works, but I am curious as to whether there is a more efficient / proper way of doing this. Thanks in advance for the knowledge-boost!
PHP
//Pull data from settings update
$gold=$_POST['gold'];
$silver=$_POST['silver'];
$plat=$_POST['plat'];
//Configure and Connect to the Database
include_once('creds.php');
include_once('db_conn.php');
mysqli_select_db($con,"metals");
//Insert Data into table & return status
$select="Select * FROM metals";
$query=mysqli_query($con,$select);
$update="UPDATE metals SET value = '".$gold."' WHERE id = 1";
$update2="UPDATE metals SET value = '".$silver."' WHERE id = 2";
$update3="UPDATE metals SET value = '".$plat."' WHERE id = 3";
$query=mysqli_query($con,$update);
$query2=mysqli_query($con,$update2);
$query3=mysqli_query($con,$update3);
if($query && $query2 && $query3){
echo "Updated!";
}
else{ echo "An error occurred!"; };
mysqli_close($con);
回答1:
Why not use the metal name as your key?
$update="UPDATE metals SET value = '".$gold."' WHERE type = 'gold'";
And you really need to switch to prepared statements. You're wide open to SQL injection
回答2:
You could use a CASE
clause like this:
$query = "UPDATE metals SET value = CASE id WHEN 1 THEN $gold WHEN 2 THEN $silver WHEN 3 THEN $plat END";
This seems a bit of overkill for just three rows, though.
来源:https://stackoverflow.com/questions/19967943/update-multiple-rows-in-one-php