I have an iOS app that needs to process a response from a web service. The response is a serialized JSON string containing a serialized JSON object, looking something like this:
"{ \"name\" : \"Bob\", \"age\" : 21 }"
Note that this response is a JSON string, not a JSON object. What I need to do is deserialize the string, so that I get this:
{ "name" : "Bob", "age" : 21 }
And then I can use +[NSJSONSerialization JSONObjectWithData:options:error:]
to deserialize that into an NSDictionary
.
But, how do I do that first step? That is, how to I "unescape" the string so that I have a serialized JSON object? +[NSJSONSerialization JSONObjectWithData:options:error:]
only works if the top-level object is an array or a dictionary; it doesn't work on strings.
I ended up writing my own JSON string parser, which I hope conforms to section 2.5 of RFC 4627. But I suspect I've overlooked some easy way to do this using NSJSONSerialization
or some other available method.
If you have nested JSON, then just call JSONObjectWithData
twice:
NSString *string = @"\"{ \\\"name\\\" : \\\"Bob\\\", \\\"age\\\" : 21 }\"";
// --> the string
// "{ \"name\" : \"Bob\", \"age\" : 21 }"
NSError *error;
NSString *outerJson = [NSJSONSerialization JSONObjectWithData:[string dataUsingEncoding:NSUTF8StringEncoding]
options:NSJSONReadingAllowFragments error:&error];
// --> the string
// { "name" : "Bob", "age" : 21 }
NSDictionary *innerJson = [NSJSONSerialization JSONObjectWithData:[outerJson dataUsingEncoding:NSUTF8StringEncoding]
options:0 error:&error];
// --> the dictionary
// { age = 21; name = Bob; }
Convert the string to data:
NSString *string = @"{ \"name\" : \"Bob\", \"age\" : 21 }";
NSData *data = [string dataUsingEncoding:NSUTF8StringEncoding];
NSError *error;
id json = [NSJSONSerialization JSONObjectWithData:data options:0 error:&error];
Just cut off the leading and trailing quotes and then replace all \"s with ":
NSString *sub = [original substringWithRange:(NSRange){ 1, original.length - 2 }];
NSString *unescaped = [sub stringByReplacingOccurrencesOfString:@"\\\" withString:@"\"];
One should first ask, why the server just don't include the JSON, as a sub structure.
But anyway. The string you got seems to be an escaped JSON. What that actually means, is totally up to the web service developer. I suspect, that just the double quotes and an escape itself have been escaped with an escape \
. The resulting string is not "serialized" - JSON is already serialized - but encoded. In order to revert it back - you need to "unescape" or decode it again:
A little C++ snippet shows how (I know you asked for Objective-C -- but this is just too easy):
Edit: the code should also work for UTF-16 and UTF-32 -- with any endianness - and if the encoder just mechanically did what I suspect, it should also work for escaped unicode characters, e.g. \u1234 etc.
Edit - no, it won't work for UTF-16 and UTF-32. The sample would have to be fixed for that (which would be easy). But please ensure you have UTF-8 - which is almost always the case.
#include <iostream>
char input[] = u8R"___({ \"name\" : \"Bob\", \"age\" : 21 })___";
// Unescapes the character sequence "in-situ".
// Returns a pointer to "past-the-end" of the unescaped string.
static char* unescape(char* first, char* last) {
char* dest = first;
while (first != last) {
if (*first == '\\') {
++first;
}
*dest++ = *first++;
}
return dest;
}
int main(int argc, const char * argv[])
{
char* first = input;
char* last = first + strlen(input);
std::string s(input, unescape(first, last));
std::cout << s << std::endl;
return 0;
}
Prints:
{ "name" : "Bob", "age" : 21 }
来源:https://stackoverflow.com/questions/16948427/how-can-you-deserialize-an-escaped-json-string-with-nsjsonserialization