问题
I am building an app using codename one
So the thing is, I need to access a URL using the app. THe URL brings back some result which I show on the screen.
SO I use these lines to do that :
ConnectionRequest c = new ConnectionRequest() {
protected void readResponse(InputStream input) throws IOException {
ByteArrayOutputStream bs = new ByteArrayOutputStream();
int ch;
while ((ch = input.read()) != -1) {
bs.write(ch);
}
serverOutput = new String(bs.toByteArray());
bs.close();
}
};
c.setUrl("My URL HERE");
c.setPost(false);
NetworkManager.getInstance().addToQueueAndWait(c);
So, now , if the gprs is active, this code works fine.
BUT , if the GPRS is inactive, it throws an Unknow Host Exception
SO to catch this error, i TRIED to use a try catch block like this:
try{
NetworkManager.getInstance().addToQueueAndWait(c);
}
catch(Exception e)
{
Sys.out.pln(e.troString());
}
But, i still get the error in the form of a dialog in the app. How do i catch this error and put my own handling for it?
UPDATE 1:
Am not sure this is necessarily a codename one specific questions, or related to java ...so just help me out with this.
回答1:
Try this to handle generic errors for all connections:
NetworkManager.getInstance().addErrorListener(new ActionListener() {
public void actionPerformed(ActionEvent evt) {
//handle your error here consume the event
evt.consume();
}
});
Or override:
protected void handleErrorResponseCode(int code, String message) {
}
And:
protected void handleException(Exception err) {
}
In your connection request code to do this for just one class.
回答2:
Try it...
public void init(Object context) {
Display.getInstance().addEdtErrorHandler(new ActionListener() {
public void actionPerformed(ActionEvent evt) {
evt.consume();
Throwable exception = (Throwable) evt.getSource();
}
});
}
来源:https://stackoverflow.com/questions/11598241/catching-unknown-host-exception-in-codename-one