c++ data members initialization order when using initialization list

问题

class A
{
private:
int a; 
int b; 
int c;

public:
A() : b(2), a(1), c (3)
{
}
};

As per C++ standard data members are constructed and initialized in the order they are declared, correct?

But when using initalization list, we are changing the order of data members, now do they initialize in order of initialization list or the order of declaration?

回答1:

In the order of declaration, the order in the initialization list does not matter. Some compilers will actually give you warning (gcc) telling you that the initialization list order is different than the order of declaration. This is why you also have to be careful when you would use members to initialize other members, etc.

回答2:

No, the initialization list has nothing to do with it.

Members are always initialized in the order in which they appear in the class body.

Some compilers will even warn you if the orders are different.

回答3:

They initialize in order of declaration. Also lot of compilers warn you that your initialization list does not match with declaration order, despite standard allows it.

回答4:

In C++11 you can also do:

class A
{
    private:
    int a = 1; 
    int b = 2; 
    int c = 3; 

public:
    A()
    {
       // your code
    }
};

回答5:

class data members are always initialized in top->bottom order of their declaration inside class and destructed in reverse order. Initialization list doesn't affects the order of initialization of data members.

You can check below related question as well for more tricky situations while using initialization lists,

How function call is working on an unitialized data member object in constructor's initilalizer list

来源：https://stackoverflow.com/questions/12126209/c-data-members-initialization-order-when-using-initialization-list

标签

c++

constructor

initializer-list