问题
I wrote a simple C program and compiled it for 32 bit architecture.
But when I ran it, I found unexpected results.
#include <stdio.h>
int foo(int n) {
int sum=0;
int i;
if (n <= 1 || n >= 0x1000)
return n;
for (i=0; i<= n; i++) {
sum = sum + i;
}
return foo(sum);
}
int main(int argc, char** argv) {
int n;
n = foo(200);
printf("\n\n main about to return %d \n\n", n);
return n;
}
➜ wbench gcc -o test.elf test.c -m32 -fno-stack-protector -mpreferred-stack-boundary=2 -Wall
➜ wbench ./test.elf
main about to return 20100
➜ wbench echo $?
132
I'm expecting 20100
to be the return value, as printed by the main function.
But, I'm getting 132
as the exit code.
I verified using GDB that 20100
is the value in the eax
register when main is about to return.
➜ wbench gdb -q test.elf
gdb-peda$ b *main+44
Breakpoint 1 at 0x8048492
gdb-peda$ r
main about to return 20100
Breakpoint 1, 0x08048492 in main ()
0x8048489 <main+35>: call 0x80482f0 <printf@plt>
0x804848e <main+40>: mov eax,DWORD PTR [ebp-0x4]
0x8048491 <main+43>: leave
=> 0x8048492 <main+44>: ret
0x8048493: xchg ax,ax
gdb-peda$ p/d $eax
$1 = 20100
gdb-peda$ c
[Inferior 1 (process 32172) exited with code 0204]
Warning: not running or target is remote
gdb-peda$ p/d 0204
$2 = 132
I even verified that when control is transferred back to __libc_start_main
and exit
function is being called, 20100
is being pushed as argument to exit()
.
gdb-peda$ r
main returning 20100
Breakpoint 1, 0x08048492 in main ()
gdb-peda$ finish
=> 0xf7e1ca83 <__libc_start_main+243>: mov DWORD PTR [esp],eax
0xf7e1ca86 <__libc_start_main+246>: call 0xf7e361e0 <exit>
0xf7e1ca8b <__libc_start_main+251>: xor ecx,ecx
gdb-peda$ si
=> 0xf7e1ca86 <__libc_start_main+246>: call 0xf7e361e0 <exit>
0xf7e1ca8b <__libc_start_main+251>: xor ecx,ecx
gdb-peda$ x/wd $esp
0xffffd5c0: 20100
What could possibly be the reason for this ?
I don't think the exit code 132
here has got anything to do with SIGILL
because when I changed the hardcoded argument to foo()
from 200
to 2
, the exit code changed to 172
where the expected exit code is 26796
.
回答1:
It looks like what you're doing is invalid, as you only have 8 bits to return to the OS.
Assuming you're linking against libc
:
When a program exits, it can return to the parent process a small amount of information about the cause of termination, using the exit status. This is a value between 0 and 255 that the exiting process passes as an argument to exit.
As indicated in its documentation here. Also relevant is this line:
Warning: Don’t try to use the number of errors as the exit status. This is actually not very useful; a parent process would generally not care how many errors occurred. Worse than that, it does not work, because the status value is truncated to eight bits. Thus, if the program tried to report 256 errors, the parent would receive a report of 0 errors—that is, success.
回答2:
20100
decimal is 4E84
hex.132
decimal is 84
hex.
Your shell is receiving the return value as only 8 bits.
回答3:
While your program may be returning 20100, the system only fetches the lowest byte, e.g return % 256
So 20100 % 256 = 132
来源:https://stackoverflow.com/questions/31815346/unexpected-exit-code-for-a-c-program-compiled-for-32-bit-architecture-using-gcc