问题
I'm having trouble understanding C's rules for what precision to assume when printing doubles, or when converting strings to doubles. The following program should illustrate my point:
#include <errno.h>
#include <float.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(int argc, char **argv) {
double x, y;
const char *s = "1e-310";
/* Should print zero */
x = DBL_MIN/100.;
printf("DBL_MIN = %e, x = %e\n", DBL_MIN, x);
/* Trying to read in floating point number smaller than DBL_MIN gives an error */
y = strtod(s, NULL);
if(errno != 0)
printf(" Error converting '%s': %s\n", s, strerror(errno));
printf("y = %e\n", y);
return 0;
}
The output I get when I compile and run this program (on a Core 2 Duo with gcc 4.5.2) is:
DBL_MIN = 2.225074e-308, x = 2.225074e-310
Error converting '1e-310': Numerical result out of range
y = 1.000000e-310
My questions are:
- Why is x printed as a nonzero number? I know compilers sometimes promote doubles to higher precision types for the purposes of computation, but shouldn't printf treat x as a 64-bit double?
- If the C library is secretly using extended precision floating point numbers, why does strtod set errno when trying to convert these small numbers? And why does it produce the correct result anyway?
- Is this behavior just a bug, a result of my particular hardware and development environment? (Unfortunately I'm not able to test on other platforms at the moment.)
Thanks for any help you can give. I will try to clarify the issue as I get feedback.
回答1:
Because of the existence of denormal numbers in the IEEE-754 standard.
DBL_MIN
is the smallest normalised value.Because the standard says so (C99 7.20.1.3):
If the result underflows (7.12.1), the functions return a value whose magnitude is no greater than the smallest normalized positive number in the return type; whether errno acquires the value ERANGE is implementation-defined.
Returning the "correct" value (i.e. 1e-310) obeys the above constraint.
So not a bug. This is technically platform-dependent, because the C standard(s) place no requirements on the existence or behaviour of denormal numbers (AFAIK).
回答2:
Here is what the standard says for strtod
underflow (C99, 7.20.1.3p10)
"If the result underflows (7.12.1), the functions return a value whose magnitude is no greater than the smallest normalized positive number in the return type; whether errno acquires the value ERANGE is implementation-defined."
Regarding ERANGE
on strtod
underflow, here is what glibc says
"When underflow occurs, the underflow exception is raised, and zero (appropriately signed) is returned. errno may be set to ERANGE, but this is not guaranteed."
http://www.gnu.org/savannah-checkouts/gnu/libc/manual/html_node/Math-Error-Reporting.html
(Note that this page is explicitly linked on glibc strtod
page "Parsing of Floats":
http://www.gnu.org/savannah-checkouts/gnu/libc/manual/html_node/Parsing-of-Floats.html
来源:https://stackoverflow.com/questions/8794576/odd-behavior-when-converting-c-strings-to-from-doubles