Compress file with dotnetzip, and when open it is corrupted

问题

I create a zip file in a controller from a byte array and I return the zip file as a fileresult. When I download the zip File and extract the file, it is corrupt. I'm doing it this way:

byte[] fileBytes =array
MemoryStream fileStream = new MemoryStream(fileBytes);
MemoryStream outputStream = new MemoryStream();
fileStream.Seek(0, SeekOrigin.Begin);

using (ZipFile zipFile = new ZipFile())
{
    zipFile.AddEntry(returnFileName, fileStream);
    zipFile.Save(outputStream);
}

outputStream.Position = 0;

FileStreamResult fileResult = new FileStreamResult(outputStream, System.Net.Mime.MediaTypeNames.Application.Zip);
fileResult.FileDownloadName = returnFileName + ".zip";

return fileResult;

回答1:

You might be unlucky hitting one of the open bugs in DotNetZip. There is e.g. an issue depending on the file size (https://dotnetzip.codeplex.com/workitem/14087).

Unfortunately, DotNetZip has some critical issues and the project seems no longer be actively be maintained. Better alternatives would be to use SharpZipLib (if you comply with their GPL-based license), or one of the .NET ports of zlib.

If you are on .NET 4.5 you can use the built-in classes in the System.IO.Compression namespace. The following sample can be found in the documentation of the ZipArchive class:

using System;
using System.IO;
using System.IO.Compression;

namespace ConsoleApplication
{
    class Program
    {
        static void Main(string[] args)
        {
            using (var zipToOpen = 
                new FileStream(@"c:\tmp\release.zip", FileMode.Open))
            {
                using (var archive = 
                     new ZipArchive(zipToOpen, ZipArchiveMode.Update))
                {
                    var readmeEntry = archive.CreateEntry("Readme.txt");
                    using (var writer = new StreamWriter(readmeEntry.Open()))
                    {
                            writer.WriteLine("Information about this package.");
                            writer.WriteLine("========================");
                    }
                }
            }
        }
    }
}

回答2:

public class HomeController : Controller
{
    public FileResult Index()
    {
        FileStreamResult fileResult = new FileStreamResult(GetZippedStream(), System.Net.Mime.MediaTypeNames.Application.Zip);
        fileResult.FileDownloadName = "result" + ".zip";
        return fileResult;
    }

    private static Stream GetZippedStream()
    {
        byte[] fileBytes = Encoding.ASCII.GetBytes("abc");
        string returnFileName = "something";

        MemoryStream fileStream = new MemoryStream(fileBytes);
        MemoryStream resultStream = new MemoryStream();

        using (ZipFile zipFile = new ZipFile())
        {
            zipFile.AddEntry(returnFileName, fileStream);
            zipFile.Save(resultStream);
        }

        resultStream.Position = 0;
        return resultStream;
    }
}

来源：https://stackoverflow.com/questions/14213763/compress-file-with-dotnetzip-and-when-open-it-is-corrupted

标签

asp.net-mvc

dotnetzip