How do I find the current directory of a batch file, and then use it for the path?

折月煮酒 提交于 2019-11-27 12:16:18
ElektroStudios

There is no need to know where the files are, because when you launch a bat file the working directory is the directory where it was launched (the "master folder"), so if you have this structure:

.\mydocuments\folder\mybat.bat
.\mydocuments\folder\subfolder\file.txt

And the user starts the "mybat.bat", the working directory is ".\mydocuments\folder", so you only need to write the subfolder name in your script:

@Echo OFF
REM Do anything with ".\Subfolder\File1.txt"
PUSHD ".\Subfolder"
Type "File1.txt"
Pause&Exit

Anyway, the working directory is stored in the "%CD%" variable, and the directory where the bat was launched is stored on the argument 0. Then if you want to know the working directory on any computer you can do:

@Echo OFF
Echo Launch dir: "%~dp0"
Echo Current dir: "%CD%"
Pause&Exit

ElektroStudios answer is a bit misleading.

"when you launch a bat file the working dir is the dir where it was launched" This is true if the user clicks on the batch file in the explorer.

However, if the script is called from another script using the CALL command, the current working directory does not change.

Thus, inside your script, it is better to use %~dp0subfolder\file1.txt

Please also note that %~dp0 will end with a backslash when the current script is not in the current working directory. Thus, if you need the directory name without a trailing backslash, you could use something like

call :GET_THIS_DIR
echo I am here: %THIS_DIR%
goto :EOF

:GET_THIS_DIR
pushd %~dp0
set THIS_DIR=%CD%
popd
goto :EOF

You can also do

 Pushd "%~dp0"

Which also takes running from a unc path into consideration.

Try in yourbatch

set "batchisin=%~dp0"

which should set the variable to your batch's location.

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