问题
I have a script that is looking for informations in web text pages and then store them in a dictionary. The script is looking for URL in a list and then process them all in a loop, however it get interrupted in the middle of the process by this error:
Traceback (most recent call last):
File "<stdin>", line 3, in <module>
File "/usr/lib/python2.7/urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout)
File "/usr/lib/python2.7/urllib2.py", line 406, in open
response = meth(req, response)
File "/usr/lib/python2.7/urllib2.py", line 519, in http_response
'http', request, response, code, msg, hdrs)
File "/usr/lib/python2.7/urllib2.py", line 444, in error
return self._call_chain(*args)
File "/usr/lib/python2.7/urllib2.py", line 378, in _call_chain
result = func(*args)
File "/usr/lib/python2.7/urllib2.py", line 527, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 300: Multiple Choices
I have problems to interpret that and I don't know if there is a way to avoid this kind of problems. Is there a way to add an exception in the script?
Here is my script:
import urllib2
import sys
import re
IDlist = ['C9JVZ1', 'C9JLN0', 'C9J872'] #(there is more than 1500 of them)
URLlist = ["http://www.uniprot.org/uniprot/"+x+".txt" for x in IDlist]
function_list = {}
for id, item in zip(IDlist, URLlist):
function_list[id] = []
textfile = urllib2.urlopen(item);
myfile = textfile.readlines();
for line in myfile:
print "line:", line;
found = re.search('\s[C]:(.+?);', line);
if found:
function = found.group(1);
function_list[id].append(function)
回答1:
The web server is returning the HTTP status code 300 Multiple Choices (see Wikipedia) for one of the URLs you want to access. This probably means one of the URLs in your list is wrong and the web server wants to help you by providing a list of similar existing URLs.
In general urllib2
turns anything thats not a success or a simple redirection response into an exception and that's what you see there.
When you don't handle an exception somewhere e.g. with a try-except
block it usually terminates your program. So you need to wrap your call to urlopen
in a try block:
try:
textfile = urllib2.urlopen(item);
except urllib2.HTTPError:
# Do something here to handle the error. For example:
print("URL", item, "could not be read.")
continue
来源:https://stackoverflow.com/questions/32641862/python-urllib2-httperror-http-error-300-multiple-choices