问题
Sorry if this is repetitive, but I've looked everywhere and can't seem to find anything that addresses my specific problem in R. I have a column with city names:
cities <-data.frame(c("Sydney", "Dusseldorf", "LidCombe", "Portland"))
colnames(cities)[1]<-"CityName"
Ideally I'd like to attach a column with either the lat/long for each city or the time zone. I have tried using the "ggmap" package in R, but my request exceeds the maximum number of requests they allow per day. I found the "geonames" package that converts lat/long to timezones, so if I get the lat/long for the city I should be able to take it from there.
Edit to address potential duplicate question: I would like to do this without using the ggmap package, as I have too many rows and they have a maximum # of requests per day.
回答1:
You can get at least many major cities from the world.cities data in the maps package.
## Changing your data to a vector
cities <- c("Sydney", "Dusseldorf", "LidCombe", "Portland")
## Load up data
library(maps)
data(world.cities)
world.cities[match(cities, world.cities$name), ]
name country.etc pop lat long capital
36817 Sydney Australia 4444513 -33.87 151.21 0
10026 Dusseldorf Germany 573521 51.24 6.79 0
NA <NA> <NA> NA NA NA NA
29625 Portland Australia 8757 -38.34 141.59 0
Note: LidCombe was not included.
Warning: For many names, there is more than one world city. For example,
world.cities[grep("Portland", world.cities$name), ]
name country.etc pop lat long capital
29625 Portland Australia 8757 -38.34 141.59 0
29626 Portland USA 542751 45.54 -122.66 0
29627 Portland USA 62882 43.66 -70.28 0
Of course the two in the USA are Portland, Maine and Portland, Oregon.
match is just giving the first one on the list. You may need to use more information than just the name to get a good result.
来源：https://stackoverflow.com/questions/46135055/how-do-i-convert-city-names-to-time-zones