第0关
http://www.pythonchallenge.com/pc/def/0.html
>>>print 2 ** 38
274877906944L
替换网址为http://www.pythonchallenge.com/pc/def/274877906944.html
第1关
http://www.pythonchallenge.com/pc/def/map.html
是个密码,字母往后移动两位,yz 变为 ab
#!/usr/bin/env python
# coding: utf-8
# author: toddlerya
# date: 2015-1-27
alpha = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n',
'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']
goal = """g fmnc wms bgblr rpylqjyrc gr zw fylb.
rfyrq ufyr amknsrcpq ypc dmp. bmgle gr gl zw fylb
gq glcddgagclr ylb rfyr'q ufw rfgq rcvr gq qm jmle.
sqgle qrpgle.kyicrpylq() gq pcamkkclbcb. lmu ynnjw ml rfc spj."""
alpha_dict = {'a': 0, 'c': 2, 'b': 1, 'e': 4, 'd': 3, 'g': 6, 'f': 5,
'i': 8, 'h': 7, 'k': 10, 'j': 9, 'm': 12, 'l': 11, 'o': 14,
'n': 13, 'q': 16, 'p': 15, 's': 18, 'r': 17, 'u': 20, 't': 19,
'w': 22, 'v': 21, 'y': 24, 'x': 23, 'z': 25}
result_dict = {0: 'a', 1: 'b', 2: 'c', 3: 'd', 4: 'e', 5: 'f', 6: 'g', 7: 'h',
8: 'i', 9: 'j', 10: 'k', 11: 'l', 12: 'm', 13: 'n', 14: 'o',
15: 'p', 16: 'q', 17: 'r', 18: 's', 19: 't', 20: 'u',
21: 'v', 22: 'w', 23: 'x', 24: 'y', 25: 'z'}
#alpha_dict = dict([ (alpha[i], i) for i in range(0,26)] )
#result_dict = dict([ (i, alpha[i]) for i in range(0,26)] )
result_order = []
result = []
for a in goal:
if a in alpha:
i = alpha_dict[a]
if i < 24:
j = i + 2
result_order.append(j)
elif 24 == i:
j = 0
result_order.append(j)
elif 25 == i:
j = 1
result_order.append(j)
#print result_order
for r in result_order:
x = result_dict[r]
result.append(x)
#print result
num = 0
for a in goal:
if a in alpha_dict:
print result[num],
num += 1
else:
print a,
过关密码:
i h o p e y o u d i d n t t r a n s l a t e i t b y h a n d .
t h a t s w h a t c o m p u t e r s a r e f o r . d o i n g i t i n b y h a n d
i s i n e f f i c i e n t a n d t h a t ' s w h y t h i s t e x t i s s o l o n g .
u s i n g s t r i n g . m a k e t r a n s ( ) i s r e c o m m e n d e d . n o w a p p l y o n t h e u r l .
按照提示改了下,好简洁。。。自己造轮子写的真丑。。。
#!/usr/bin/env python
# coding: utf-8
# author: toddlerya
# date: 2015-1-27
from string import maketrans
in_string = "abcdefghijklmnopqrstuvwxyz"
out_string = "cdefghijklmnopqrstuvwxyzab"
goal = """g fmnc wms bgblr rpylqjyrc gr zw fylb.
rfyrq ufyr amknsrcpq ypc dmp. bmgle gr gl zw fylb
gq glcddgagclr ylb rfyr'q ufw rfgq rcvr gq qm jmle.
sqgle qrpgle.kyicrpylq() gq pcamkkclbcb. lmu ynnjw ml rfc spj."""
trans_string = maketrans(in_string, out_string)
print goal.translate(trans_string)
这次输出的好看多了:
i hope you didnt translate it by hand.
thats what computers are for. doing it in by hand
is inefficient and that's why this text is so long.
using string.maketrans() is recommended. now apply on the url.
第2关
http://www.pythonchallenge.com/pc/def/ocr.html
从提示可知道,查看源代码,找到一段注释
<!--
find rare characters in the mess below:
-->
<!--
%%$@_$^__#)^)&!_+]!*@&^}@[@%]()%+$&[(_@%+%$*^@$^!+]!&_#)_*}{}}!}_]$[%}@[{_@#_^{*
@##&{#&{&)*%(]{{([*}@[@&]+
……
-->
#!/usr/bin/env python
# coding: utf-8
# author: toddlerya
# date: 2015-1-27
# 把那一段注释里的内容 放到rare_char里面
rare_char = """
%%$@_$^__#)^)&!_+]!*@&^}@[@%]()%
省略n行
"""
tmp = []
for i in rare_char:
if i in tmp:
pass
else:
tmp.append(i)
print i, rare_char.count(i)
运行结果如下:
toddler@HP:~/Desktop$ python 3.py
1220
% 6104
$ 6046
@ 6157
_ 6112
^ 6030
# 6115
) 6186
& 6043
! 6079
+ 6066
] 6152
* 6034
} 6105
[ 6108
( 6154
{ 6046
e 1
q 1
u 1
a 1
l 1
i 1
t 1
y 1
可以看到最少字符是equality。这就是过关密码啦。改下url,下一关
第3关
http://www.pythonchallenge.com/pc/def/equality.html
目标要求的格式为xXXXxXXXx 正则搞定
那段待处理的文字放在src里
#!/usr/bin/env python
# coding: utf-8
# author: toddlerya
# date: 2015-1-28
import re
src = """
kAewtloYgcFQaJNhHVGxXDiQmz
……
"""
goal = re.findall("[a-z]{1}[A-Z]{3}[a-z]{1}[A-Z]{3}[a-z]{1}", src)
i = 0
for g in goal:
print goal[i][4],
i += 1
过关密码:
>>>
l i n k e d l i s t
替换equality为linkedlist
显示linkedlist.php
替换网址为linkedlist.php
进入第四关
第4关
http://www.pythonchallenge.com/pc/def/linkedlist.php
点击图片跳转到新的页面,提示 :and the next nothing is 44827
看下网址:http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=12345
改下好了:http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=44827
……
改了两次发现这个应该用Python获取网络连接,然后改url访问下一次直到成功。。。
蠢哭了。。。
上Python
#!/usr/bin/env python
# coding: utf-8
# author: toddlerya
# date: 2015-1-28
import urllib2, re
nothing = "12345"
url_nothing = "http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing="
url = url_nothing + nothing
count = 1
while nothing:
try:
response = urllib2.urlopen(url, timeout=60)
html = response.read()
tmp = re.findall("[0-9]+", html)
nothing = ''.join(tmp)
url = url_nothing + nothing
print count, "\n", url
count += 1
except:
print html
这个网络也是醉了。。。等了好久。。。
最后结果
85
http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=16044
86
http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=
访问:http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=16044
提示信息:Yes. Divide by two and keep going.
改下代码nothing="8022",继续跑!!!丧心病狂啊
http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=66831
拿到密码:peak.html
第5关:
http://www.pythonchallenge.com/pc/def/peak.html
来源:oschina
链接:https://my.oschina.net/u/2003106/blog/372436