How to make a simple jQuery filter list accept only whole words, so it doesn't match partial words, only whole words

大兔子大兔子 提交于 2020-01-02 13:53:08

问题


http://jsfiddle.net/nicktheandroid/U8T8p/4/

(function($) {

    $('.filterinput').keyup(function() {
        var filter = $(this).val();
        if (filter.length > 2) {
            // this finds all links in the list that contain the input,
            // and hide the ones not containing the input while showing the ones that do
            $(list).find("a:not(:Contains(" + filter + "))").parent().slideUp();
            $(list).find("a:Contains(" + filter + ")").parent().slideDown();
        } else {
            $(list).find("li").slideDown();
        }
        return false;
    })

}(jQuery));

This will filter the list based on if what you've typed matches ANY part of a word in the list. I'm trying to make it only match whole words, so it wont say it has a match until the full word is typed. Would Regex be best? Or? I need help, nothing I've tried has worked.


回答1:


Something like this: http://jsfiddle.net/U8T8p/10/

        var containing = $('#list li').filter(function () {
            var regex = new RegExp('\\b' + a, 'i');
            return regex.test($('a', this).text());
        }).slideDown();
        $('#list li').not(containing).slideUp();

The regex limits matches to those where the currently entered text starts at a word boundary. So, having typed 'Stat' you'd still match 'United States'. You can make it match a full word by changing to RegExp('\\b' + a + '\\b', i).




回答2:


You can make use of the filter method as already mentioned. Or you can easily extend jQuery with your own custom filter which is great way to reuse code.

$.expr[':'].containsWord = function(elem, index, match) {
    var text = $(elem).text();
    return !!text.match(new RegExp('\\b' + match[3] + '\\b'));
};

and now use it like you would do with any other built-in filter :containsWord('Some word'). See http://jsfiddle.net/U8T8p/9/




回答3:


Try something like this: http://jsfiddle.net/U8T8p/5/

$(list).find("a").filter(function() { return $(this).text() != filter; }).parent().slideUp();
$(list).find("a").filter(function() { return $(this).text() === filter; }).parent().slideDown();



回答4:


You can use .filter to check the texts and slide these elements down, and pass these elements as a jQuery object to .not to get the other elements to slide up: http://jsfiddle.net/U8T8p/8/.

(function($) {

    $('.filterinput').keyup(function() {
        var filter = $(this).val();
        if (filter.length > 2) {
            var a = $(list).find("a");

            var x = a.filter(function() {
                return $(this).text() === filter;
            });

            x.parent().slideDown();

            a.not(x).parent().slideUp();
        } else {
            $(list).find("li").slideDown();
        }
        return false;
    })

}(jQuery));


来源:https://stackoverflow.com/questions/8688929/how-to-make-a-simple-jquery-filter-list-accept-only-whole-words-so-it-doesnt-m

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