Illegal polymorphic or qualified type using RankNTypes and TypeFamilies

问题

I've been slowly working on porting the llvm package to use data kinds, type families and type-nats and ran into a minor issue when trying to remove the two newtypes used for classifying values (ConstValue and Value) by introducing a new Value type parameterized by its constness.

CallArgs only accepts Value 'Variable a arguments and provides a function for casting a Value 'Const a to a Value 'Variable a. I'd like to generalize CallArgs to allow each argument to be either 'Const or 'Variable. Is this possible to encode this somehow using type families? I think it's probably doable with fundeps.

{-# LANGUAGE DataKinds #-}
{-# LANGUAGE RankNTypes #-}
{-# LANGUAGE TypeFamilies #-}

data Const = Const | Variable

data Value (c :: Const) (a :: *)

type family CallArgs a :: * 
type instance CallArgs (a -> b) = forall (c :: Const) . Value c a -> CallArgs b
type instance CallArgs (IO a)   = IO (Value 'Variable a)

... which fails to compile:

/tmp/blah.hs:10:1:
    Illegal polymorphic or qualified type:
      forall (c :: Const). Value c a
    In the type instance declaration for `CallArgs'

Where the following solution works (equivalent to the legacy code), but requires the user to cast the each constant Value:

type family CallArgs' a :: * 
type instance CallArgs' (a -> b) = Value 'Variable a -> CallArgs' b
type instance CallArgs' (IO a)   = IO (Value 'Variable a)

回答1:

The CallArgs you're asking for is kind of like a non-deterministic function which takes a -> b and returns either Value 'Const a -> blah or Value 'Variable a -> blah. One thing you can sometimes to with nondeterministic functions is flip them around; indeed, this one has a deterministic inverse.

type family   UnCallArgs a
type instance UnCallArgs (Value c a -> b) = a -> UnCallArgs b
type instance UnCallArgs (IO 'Variable a) = IO a

Now, anywhere you would have written a type like

foo :: CallArgs t -> LLVM t

or something like that, you can write this instead:

foo :: t -> LLVM (UnCallArgs t)

Of course, you might want to pick a better name than UnCallArgs, maybe Native or something like that, but doing that well requires a bit of domain knowledge that I don't have.

回答2:

Would wrapping the forall c. in a newtype AV work for you?

{-# LANGUAGE DataKinds #-}
{-# LANGUAGE RankNTypes #-}
{-# LANGUAGE TypeFamilies #-}

data CV = Const | Variable

data Value (c :: CV) (a :: *)

data AV a = AV (forall c. Value c a)

type family CallArgs a :: * 
type instance CallArgs (a -> b) = AV a -> CallArgs b
type instance CallArgs (IO a)   = IO (Value 'Variable a)

来源：https://stackoverflow.com/questions/13846284/illegal-polymorphic-or-qualified-type-using-rankntypes-and-typefamilies

标签

haskell

type-families