问题
I have this CSS rule for rounded corner:
th, td { padding: 8px;
background: #E8ECE0;
text-align: center;
border: 1px solid #444;
border-bottom-width: 0px;
}
thead { background-color: #446bb3 ; color :#fff; padding:4px; line-height:30px }
tbody tr:nth-child(even) {background: #F6F6EC;}
tbody tr:nth-child(odd) {background: #FFF}
tr:first-child td, tr:first-child th {
border-top-left-radius: 12px; border-top-right-radius: 12px;
}
tr:last-child td {
border-bottom: 1px solid #444;
border-bottom-left-radius: 12px; border-bottom-right-radius: 12px;
}
table { border-spacing: 0; border: 0; margin:0px; width:100%; padding:5px}
td.pd {border-bottom-left-radius: 12px; border-bottom-right-radius: 12px;}
td.pu {border-top-left-radius: 12px; border-top-right-radius: 12px;}
My html table is:
<table >
<tbody>
<tr >
<td >Hello</td><td >Hello</td>
</tr>
<tr >
<td >Hello</td><td >Hello</td>
</tr>
<tr >
<td >Hello</td><td >Hello</td>
</tr>
<tr >
<td >Hello</td><td >Hello</td>
</tr>
</tbody>
</table>
which gives me this
How do I fix this problem, as the td elements within the table and in the middle of the table have rounded corners too? I only need the first row and last row to have rounded corners.
回答1:
Assuming your table's html resembles the following:
<table>
<thead>
<tr>
<th>First column</th>
<th>Second column</th>
</tr>
</thead>
<tbody>
<tr>
<td>Row one, cell one</td>
<td>Row one, cell two</td>
</tr>
<tr>
<td>Row two, cell one</td>
<td>Row two, cell two</td>
</tr>
<tr>
<td>Row three, cell one</td>
<td>Row four, cell two</td>
</tr>
</tbody>
</table>
The the following CSS should work:
table {
border-spacing: 0;
}
th, td {
border: 1px solid #000;
padding: 0.5em 1em;
}
/* the first 'th' within the first 'tr' of the 'thead': */
thead tr:first-child th:first-child {
border-radius: 0.6em 0 0 0;
}
/* the last 'th' within the first 'tr' of the 'thead': */
thead tr:first-child th:last-child {
border-radius: 0 0.6em 0 0;
}
/* the first 'td' within the last 'tr' of the 'tbody': */
tbody tr:last-child td:first-child {
border-radius: 0 0 0 0.6em;
}
/* the last 'td' within the last 'tr' of the 'tbody': */
tbody tr:last-child td:last-child {
border-radius: 0 0 0.6em 0;
}
JS Fiddle demo.
Edited in response to question from OP:
the border within the table is a little think, how do i make it 1px
The borders between cells are a little thick, because the left border of one cell is against the right border of the previous cells (and the same for top/bottom borders).
One way to remove that effect is to specify border-collapse: collapse; on the table element. Unfortunately the effect of this is to also remove/unset/override the border-radius declarations: demo.
The more complicated way is to manually remove top-borders for rows with a previous row, and the left-border of a cell that follows a cell, adding the following to the previous CSS:
thead + tbody tr td,
tr + tr td {
border-top: 0;
}
tr th + th,
tr td + td {
border-left: 0;
}
JS Fiddle demo.
Edited to reduce make the CSS more durable (for single-cell rows, for the addition of a tfoot or the removal of the thead):
table {
border-spacing: 0;
}
th, td {
border: 1px solid #000;
padding: 0.5em 1em;
}
thead tr:first-child th:first-child,
tbody:first-child tr:first-child td:first-child {
border-top-left-radius: 0.6em;
}
thead tr:first-child th:last-child,
tbody:first-child tr:first-child td:last-child {
border-top-right-radius: 0.6em;
}
thead + tbody tr:last-child td:first-child,
tfoot tr:last-child td:first-child {
border-bottom-left-radius: 0.6em;
}
thead + tbody tr:last-child td:last-child,
tfoot tr:last-child td:last-child {
border-bottom-right-radius: 0.6em;
}
thead + tbody tr td,
tfoot + tbody tr td,
tfoot tr td,
tbody + tbody tr td,
tr + tr td {
border-top: 0;
}
tr th + th,
tr td + td {
border-left: 0;
}
JS Fiddle demo.
There is a problem with multiple tbody elements, in the absence of a tfoot element, currently in which the first tbody will retain the border-radius on their lower borders.
回答2:
You can just put table into div. Styles for div (example):
div {
border-radius: 4px;
-moz-border-radius: 4px
-webkit-border-radius: 4px;
overflow: hidden; /*notice*/
}
So the table corners will be hidden.
回答3:
This answer doesn't answer your question directly, but a variant. If you dont want the middle columns to have rounded corners, this is a possible solution:
Illustration:
Properties for the table row (tr): update the table data (td) for the left most column:
tbody tr td:first-child
{
border-radius: 0.6em 0 0 0.6em;
}
Properties for the table row (tr): update the table data (td) for the second column:
tbody td:nth-child(2)
{
border-radius: 0 0.6em 0.6em 0;
}
Here is an example: JS Fiddle demo
If you have more than one column (td or th) you simply add something like this:
tbody td:nth-child(2) /* This is now the middle element out of three */
{
border-radius: 0 0 0 0;
}
tbody td:nth-child(3) /* This is now the right most column */
{
boder-radius: 0 0.6em 0.6em 0;
}
回答4:
You can reset the border radius of the td element. That should solve it.
回答5:
You can give id to the td elements and using the id's of td elements set the border radius to 0px.
回答6:
You should try a
clear:both;
and it will be reset.
Also you can try !important because maybe you forget other "inline css rules" in other html codes.
回答7:
Though this is an old answer, I'd like to enhance it by adding my findings. In addition to David Thomas's super-smart answer, I found an edge case where it doesn't exactly fit: A single-cell row! for example:
<table>
<tr><th colspan="3">My header</th></tr>
<tr><td>row1-cell1</td><td>row1-cell2</td><td>row1-cell3</td></tr>
<tr><td>row2-cell1</td><td>row2-cell2</td><td>row2-cell3</td></tr>
<tr><th colspan="3">My footer</th></tr>
</table>
The rule for the top-right corner would overwrite the rule for the top-left corner (because it comes after it), and the rule for the bottom-right corner would overwrite the rule for the bottom left corner (for the same reason). See screen shot below:
The remedy for that is the css below (I added more selectors for various table-tr, tbody-tr, thead-tr combinations as needed, so you can also expand it to fit your markup):
table td,
table th{
border: 1px solid #666;
}
table{
width: 98%;
border-spacing: 0px;
}
/* alternating table row colors*/
tr:nth-child(even) { background-color:#f6f6f6; }
tr:nth-child(odd) { background-color:#ffffff; }
/* set all corner radii initially to zero */
th, td {
border-radius: 0;
}
/*set only specific radii per corner (don't use the border-radius shorthand)*/
thead tr:first-child th:first-child,
table tr:first-child td:first-child,
tbody tr:first-child th:first-child {
border-top-left-radius: 0.6em;
}
thead tr:first-child th:last-child,
table tr:first-child td:last-child,
tbody tr:first-child th:last-child {
border-top-right-radius: 0.6em;
}
tbody tr:last-child td:first-child,
table tr:last-child td:first-child,
tbody tr:last-child th:first-child {
border-bottom-left-radius: 0.6em;
}
tbody tr:last-child td:last-child,
table tr:last-child td:last-child,
tbody tr:last-child th:last-child {
border-bottom-right-radius: 0.6em;
}
thead + tbody tr td,
tr + tr td ,
tr + tr th {
border-top: 0;
}
tr th + th,
tr td + td {
border-left: 0;
}
/* shade th cells */
table th {
background-color: #888;
color: #FFF;
}
This results in the screenshot below, as desired:
All credit for this solution still goes to David Thomas, especially for the adjacent cells border trick!
来源：https://stackoverflow.com/questions/16635182/solving-table-rounded-corner-css