问题
What I'm trying to do is open a modal from another component, however I keep getting this error TypeError: Cannot create property 'validator' on string 'test1'
when component1.html
loads because childModal
is included. How can I get rid of these errors and implement this properly?
component1.html
<button type="button" class="btn btn-outline-primary btn-lg" (click)="modal.showModal()">Test
......
<child-modal #childModal ></child-modal>
component1.ts
@ViewChild('childModal') childModal: ModalComponent;
modal.html
<div bsModal #childModal="bs-modal" class="modal fade" tabindex="-1" role="dialog>
<div class="modal-dialog modal-lg">
<div class="modal-content">
<input type="text" formControl="test1">
<input type="text" formControl="test2">
</div>
</div>
</div>
modal.component.ts
constructor(private modalService: BsModalService) {
this.form = new FormGroup({
'test': new FormControl(),
'test2': new FormControl()
})
}
回答1:
If you're trying to open a Modal Component from another Component, then this is the right way to do it with ngx-bootstrap:
import { Component } from '@angular/core';
import { BsModalService } from 'ngx-bootstrap/modal';
import { BsModalRef } from 'ngx-bootstrap/modal/modal-options.class';
/* This is the Component from which we open the Modal Component */
@Component({
selector: 'my-component',
templateUrl: './service-component.html'
})
export class MyComponent {
bsModalRef: BsModalRef;
constructor(private modalService: BsModalService) {}
public openModalWithComponent() {
/* this is how we open a Modal Component from another component */
this.bsModalRef = this.modalService.show(ModalContentComponent);
}
}
/* This is the Modal Component */
@Component({
selector: 'child-modal',
template: `
<div class="modal-header">
<h4 class="modal-title pull-left">Title</h4>
<button type="button" class="close pull-right" aria-label="Close" (click)="bsModalRef.hide()">
<span aria-hidden="true">×</span>
</button>
</div>
<div class="modal-body">
...
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default" (click)="bsModalRef.hide()">Close</button>
</div>
`
})
export class ChildModalComponent {
constructor(public bsModalRef: BsModalRef) {}
}
template of the Component which is calling the Modal:
<button type="button" class="btn btn-primary" (click)="openModalWithComponent()">Create modal with component</button>
So you should NOT include the Modal Component in the template like this:
<child-modal #childModal ></child-modal>
Official doc:
https://valor-software.com/ngx-bootstrap/#/modals#service-component
回答2:
If you use same component then,
HTML #
<button (click)="openModalWithComponent()">open</button>
// for display purpose
<ng-template #template>
<div class="modal-body">
</div>
</ng-template>
COMPONENT #
import { BsModalRef } from 'ngx-bootstrap/modal/bs-modal-ref.service';
import { BsModalService } from 'ngx-bootstrap/modal';
import { ViewChild, ElementRef } from '@angular/core';
bsModalRef: BsModalRef;
constructor(private modalService: BsModalService) {}
@ViewChild('template') elementView: ElementRef;
openModalWithComponent() {
this.bsModalRef = this.modalService.show(this.elementView);
// this.bsModalRef.content.closeBtnName = 'Close';
// (click)="bsModalRef.hide()"
}
回答3:
you only need to add your child-component into the entryComponents in your module like this:
entryComponents: [
childComponent
]
it works for me
来源:https://stackoverflow.com/questions/46698126/ngx-bootstrap-how-to-open-a-modal-from-another-component