Get Contact by Phone number on Android

问题

I know how I can get all contacts in Android , and how to get their phone number.

What I cant seem to figure out is how to get a contact by phone number...

This is my current piece of code I wrote to test which phone numbers are available:

// Create a cursor
    Cursor cursor = Base.contentResover().query(Phone.CONTENT_URI, null, null,
            null, null);

    if (cursor.moveToNext()) {
        Log.d("CALLOG", cursor.getString(cursor.getColumnIndexOrThrow(Phone.NUMBER)));
    }

The problem is that i only get a few phone numbers returned, while i expect to get all... What am I doing wrong?

回答1:

I dont think there is anything wrong with the snippet that you had pasted. Try using a while loop to LOG all the phone numbers.

Regarding your requirement to fetch a contact by Phone Number.Try using the following snippet

Uri uri = Uri.withAppendedPath(PhoneLookup.CONTENT_FILTER_URI, Uri.encode(phoneNumber)); 
resolver.query(uri, new String[]{PhoneLookup.DISPLAY_NAME,PhoneLookup._ID...

Use the _ID to determine the contact.

Why to use PhoneLookup instead of Phone?

The PhoneLookup is highly optimised in terms of its searches.
Phone numbers can be entered in the contacts database with fillers like "(",")","-" etc PhoneLookup
helps to decouple these fillers and compare only the phone number.
Comparing the values from Phone will not fetch you any result.
It provides various other phone number related info. (HAS_PHONE_NUMBER,TIMES_CONTACTED,DISPLAY_NAME etc)

Hope that helps. Let me know if you need anything else.

回答2:

You can use this method to get all your contact with name,_id and no. You can call this method in your Activity.

private void displayContacts() {

        ContentResolver cr = getContentResolver();
        Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI,
                null, null, null, null);
        if (cur.getCount() > 0) {
            while (cur.moveToNext()) {
                String id = cur.getString(cur.getColumnIndex(ContactsContract.Contacts._ID));
                String name = cur.getString(cur.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));

                if (Integer.parseInt(cur.getString(cur.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) {
                     Cursor pCur = cr.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,null,
                                 ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = ?", new String[]{id}, null);
                     while (pCur.moveToNext()) {
                         String phoneNo = pCur.getString(pCur.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));

                         System.out.println("name"+name+"ph no"+phoneNo);
                         Toast.makeText(this, "Name: " + name + ", Phone No: " + phoneNo, Toast.LENGTH_SHORT).show();
                     } 
                pCur.close();
            }
            }
        }
    }

回答3:

Use this kind of code:

public void logCallLog(String number)
{
    long dialed;
    String columns[]=new String[] {
            CallLog.Calls._ID,
            CallLog.Calls.NUMBER,
            CallLog.Calls.DATE,
            CallLog.Calls.DURATION,
            CallLog.Calls.TYPE};
    String args[]=new String[1];
    args[0]=number;
    Cursor c;
    c = this.managedQuery(Uri.parse("content://call_log/calls"),
            columns, CallLog.Calls.NUMBER+"=?", args, "Calls._ID DESC"); //last record first
    while (c.moveToNext())
    {
        dialed=c.getLong(c.getColumnIndex(CallLog.Calls.DATE));
        if(Me.DEBUG)
            Log.v("CallLog", "Call to number: "+number+", registered at: "+new Date(dialed).toString());
    }
}

来源：https://stackoverflow.com/questions/5553867/get-contact-by-phone-number-on-android

标签

android

cursor

android-contacts

phone-number