matrix determinant differentiation in tensorflow

自古美人都是妖i 提交于 2019-12-29 06:59:52

问题


I am interested in computing the derivative of a matrix determinant using TensorFlow. I can see from experimentation that TensorFlow has not implemented a method of differentiating through a determinant:

LookupError: No gradient defined for operation 'MatrixDeterminant' 
(op type: MatrixDeterminant)

A little further investigation revealed that it is actually possible to compute the derivative; see for example Jacobi's formula. I determined that in order to implement this means of differentiating through a determinant that I need to use the function decorator,

@tf.RegisterGradient("MatrixDeterminant")
def _sub_grad(op, grad):
    ...

However, I am not familiar enough with tensor flow to understand how this can be accomplished. Does anyone have any insight on this matter?

Here's an example where I run into this issue:

x = tf.Variable(tf.ones(shape=[1]))
y = tf.Variable(tf.ones(shape=[1]))

A = tf.reshape(
    tf.pack([tf.sin(x), tf.zeros([1, ]), tf.zeros([1, ]), tf.cos(y)]), (2,2)
)
loss = tf.square(tf.matrix_determinant(A))


optimizer = tf.train.GradientDescentOptimizer(0.001)
train = optimizer.minimize(loss)

init = tf.initialize_all_variables()
sess = tf.Session()
sess.run(init)


for step in xrange(100):
    sess.run(train)
    print sess.run(x)

回答1:


Please check "Implement Gradient in Python" section here

In particular, you can implement it as follows

@ops.RegisterGradient("MatrixDeterminant")
def _MatrixDeterminantGrad(op, grad):
  """Gradient for MatrixDeterminant. Use formula from 2.2.4 from
  An extended collection of matrix derivative results for forward and reverse
  mode algorithmic differentiation by Mike Giles
  -- http://eprints.maths.ox.ac.uk/1079/1/NA-08-01.pdf
"""
  A = op.inputs[0]
  C = op.outputs[0]
  Ainv = tf.matrix_inverse(A)
  return grad*C*tf.transpose(Ainv)

Then a simple training loop to check that it works:

a0 = np.array([[1,2],[3,4]]).astype(np.float32)
a = tf.Variable(a0)
b = tf.square(tf.matrix_determinant(a))
init_op = tf.initialize_all_variables()
sess = tf.InteractiveSession()
init_op.run()

minimization_steps = 50
learning_rate = 0.001
optimizer = tf.train.GradientDescentOptimizer(learning_rate)
train_op = optimizer.minimize(b)

losses = []
for i in range(minimization_steps):
  train_op.run()
  losses.append(b.eval())

Then you can visualize your loss over time

import matplotlib.pyplot as plt

plt.ylabel("Determinant Squared")
plt.xlabel("Iterations")
plt.plot(losses)

Should see something like this




回答2:


I think you are confused with what is a derivative of a matrix determinant.

Matrix determinant is a function which is calculated over the elements of the matrix by some formula. So if all the elements of the matrix are numbers, you the determinant will you you just one number and the derivative will be 0. When some of the elements are variables, you will get an expression of these variables. For example:

x, x^2
1, sin(x)

The determinant will be x*sin(x) - x^2 and the derivative is 2x + sin(x) + x*cos(x). The Jacobi formula just connects the determinant with adjunct matrix.


In your example your matrix A consists of only numbers and therefore the determinant is just a number and the loss is just a number as well. GradientDescentOptimizer needs to have some free variables to minimize and does not have any because your loss is just a number.




回答3:


For those who are interested, I discovered the solution that works on my problems:

@tf.RegisterGradient("MatrixDeterminant")
def _MatrixDeterminant(op, grad):
    """Gradient for MatrixDeterminant."""
    return op.outputs[0] * tf.transpose(tf.matrix_inverse(op.inputs[0]))


来源:https://stackoverflow.com/questions/33714832/matrix-determinant-differentiation-in-tensorflow

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!