问题
I'm performing matrix multiplication with this simple algorithm. To be more flexible I used objects for the matricies which contain dynamicly created arrays.
Comparing this solution to my first one with static arrays it is 4 times slower. What can I do to speed up the data access? I don't want to change the algorithm.
matrix mult_std(matrix a, matrix b) {
matrix c(a.dim(), false, false);
for (int i = 0; i < a.dim(); i++)
for (int j = 0; j < a.dim(); j++) {
int sum = 0;
for (int k = 0; k < a.dim(); k++)
sum += a(i,k) * b(k,j);
c(i,j) = sum;
}
return c;
}
EDIT
I corrected my Question avove! I added the full source code below and tried some of your advices:
- swapped
kandjloop iterations -> performance improvement - declared
dim()andoperator()()asinline-> performance improvement - passing arguments by const reference -> performance loss! why? so I don't use it.
The performance is now nearly the same as it was in the old porgram. Maybe there should be a bit more improvement.
But I have another problem: I get a memory error in the function mult_strassen(...). Why? terminate called after throwing an instance of 'std::bad_alloc'
what(): std::bad_alloc
OLD PROGRAM
main.c http://pastebin.com/qPgDWGpW
c99 main.c -o matrix -O3
NEW PROGRAM
matrix.h http://pastebin.com/TYFYCTY7
matrix.cpp http://pastebin.com/wYADLJ8Y
main.cpp http://pastebin.com/48BSqGJr
g++ main.cpp matrix.cpp -o matrix -O3.
EDIT
Here are some results. Comparison between standard algorithm (std), swapped order of j and k loop (swap) and blocked algortihm with block size 13 (block).
回答1:
Pass the parameters by const reference to start with:
matrix mult_std(matrix const& a, matrix const& b) {
To give you more details we need to know the details of the other methods used.
And to answer why the original method is 4 times faster we would need to see the original method.
The problem is undoubtedly yours as this problem has been solved a million times before.
Also when asking this type of question ALWAYS provide compilable source with appropriate inputs so we can actually build and run the code and see what is happening.
Without the code we are just guessing.
Edit
After fixing the main bug in the original C code (a buffer over-run)
I have update the code to run the test side by side in a fair comparison:
// INCLUDES -------------------------------------------------------------------
#include <stdlib.h>
#include <stdio.h>
#include <sys/time.h>
#include <time.h>
// DEFINES -------------------------------------------------------------------
// The original problem was here. The MAXDIM was 500. But we were using arrays
// that had a size of 512 in each dimension. This caused a buffer overrun that
// the dim variable and caused it to be reset to 0. The result of this was causing
// the multiplication loop to fall out before it had finished (as the loop was
// controlled by this global variable.
//
// Everything now uses the MAXDIM variable directly.
// This of course gives the C code an advantage as the compiler can optimize the
// loop explicitly for the fixed size arrays and thus unroll loops more efficiently.
#define MAXDIM 512
#define RUNS 10
// MATRIX FUNCTIONS ----------------------------------------------------------
class matrix
{
public:
matrix(int dim)
: dim_(dim)
{
data_ = new int[dim_ * dim_];
}
inline int dim() const {
return dim_;
}
inline int& operator()(unsigned row, unsigned col) {
return data_[dim_*row + col];
}
inline int operator()(unsigned row, unsigned col) const {
return data_[dim_*row + col];
}
private:
int dim_;
int* data_;
};
// ---------------------------------------------------
void random_matrix(int (&matrix)[MAXDIM][MAXDIM]) {
for (int r = 0; r < MAXDIM; r++)
for (int c = 0; c < MAXDIM; c++)
matrix[r][c] = rand() % 100;
}
void random_matrix_class(matrix& matrix) {
for (int r = 0; r < matrix.dim(); r++)
for (int c = 0; c < matrix.dim(); c++)
matrix(r, c) = rand() % 100;
}
template<typename T, typename M>
float run(T f, M const& a, M const& b, M& c)
{
float time = 0;
for (int i = 0; i < RUNS; i++) {
struct timeval start, end;
gettimeofday(&start, NULL);
f(a,b,c);
gettimeofday(&end, NULL);
long s = start.tv_sec * 1000 + start.tv_usec / 1000;
long e = end.tv_sec * 1000 + end.tv_usec / 1000;
time += e - s;
}
return time / RUNS;
}
// SEQ MULTIPLICATION ----------------------------------------------------------
int* mult_seq(int const(&a)[MAXDIM][MAXDIM], int const(&b)[MAXDIM][MAXDIM], int (&z)[MAXDIM][MAXDIM]) {
for (int r = 0; r < MAXDIM; r++) {
for (int c = 0; c < MAXDIM; c++) {
z[r][c] = 0;
for (int i = 0; i < MAXDIM; i++)
z[r][c] += a[r][i] * b[i][c];
}
}
}
void mult_std(matrix const& a, matrix const& b, matrix& z) {
for (int r = 0; r < a.dim(); r++) {
for (int c = 0; c < a.dim(); c++) {
z(r,c) = 0;
for (int i = 0; i < a.dim(); i++)
z(r,c) += a(r,i) * b(i,c);
}
}
}
// MAIN ------------------------------------------------------------------------
using namespace std;
int main(int argc, char* argv[]) {
srand(time(NULL));
int matrix_a[MAXDIM][MAXDIM];
int matrix_b[MAXDIM][MAXDIM];
int matrix_c[MAXDIM][MAXDIM];
random_matrix(matrix_a);
random_matrix(matrix_b);
printf("%d ", MAXDIM);
printf("%f \n", run(mult_seq, matrix_a, matrix_b, matrix_c));
matrix a(MAXDIM);
matrix b(MAXDIM);
matrix c(MAXDIM);
random_matrix_class(a);
random_matrix_class(b);
printf("%d ", MAXDIM);
printf("%f \n", run(mult_std, a, b, c));
return 0;
}
The results now:
$ g++ t1.cpp
$ ./a.exe
512 1270.900000
512 3308.800000
$ g++ -O3 t1.cpp
$ ./a.exe
512 284.900000
512 622.000000
From this we see the C code is about twice as fast as the C++ code when fully optimized. I can not see the reason in the code.
回答2:
Speaking of speed-up, your function will be more cache-friendly if you swap the order of the k and j loop iterations:
matrix mult_std(matrix a, matrix b) {
matrix c(a.dim(), false, false);
for (int i = 0; i < a.dim(); i++)
for (int k = 0; k < a.dim(); k++)
for (int j = 0; j < a.dim(); j++) // swapped order
c(i,j) += a(i,k) * b(k,j);
return c;
}
That's because a k index on the inner-most loop will cause a cache miss in b on every iteration. With j as the inner-most index, both c and b are accessed contiguously, while a stays put.
回答3:
You say you don't want to modify the algorithm, but what does that mean exactly?
Does unrolling the loop count as "modifying the algorithm"? What about using SSE/VMX whichever SIMD instructions are available on your CPU? What about employing some form of blocking to improve cache locality?
If you don't want to restructure your code at all, I doubt there's more you can do than the changes you've already made. Everything else becomes a trade-off of minor changes to the algorithm to achieve a performance boost.
Of course, you should still take a look at the asm generated by the compiler. That'll tell you much more about what can be done to speed up the code.
回答4:
Make sure that the members dim() and operator()() are declared inline, and that compiler optimization is turned on. Then play with options like -funroll-loops (on gcc).
How big is a.dim() anyway? If a row of the matrix doesn't fit in just a couple cache lines, you'd be better off with a block access pattern instead of a full row at-a-time.
回答5:
- Use SIMD if you can. You absolutely have to use something like VMX registers if you do extensive vector math assuming you are using a platform that is capable of doing so, otherwise you will incur a huge performance hit.
- Don't pass complex types like
matrixby value - use a const reference. - Don't call a function in each iteration - cache
dim()outside your loops. - Although compilers typically optimize this efficiently, it's often a good idea to have the caller provide a matrix reference for your function to fill out rather than returning a matrix by type. In some cases, this may result in an expensive copy operation.
回答6:
Here is my implementation of the fast simple multiplication algorithm for square float matrices (2D arrays). It should be a little faster than chrisaycock code since it spares some increments.
static void fastMatrixMultiply(const int dim, float* dest, const float* srcA, const float* srcB)
{
memset( dest, 0x0, dim * dim * sizeof(float) );
for( int i = 0; i < dim; i++ ) {
for( int k = 0; k < dim; k++ )
{
const float* a = srcA + i * dim + k;
const float* b = srcB + k * dim;
float* c = dest + i * dim;
float* cMax = c + dim;
while( c < cMax )
{
*c++ += (*a) * (*b++);
}
}
}
}
回答7:
I'm taking a wild guess here, but if you dynamically allocating the matrices makes such a huge difference, maybe the problem is fragmentation. Again, I've no idea how the underlying matrix is implemented.
Why don't you allocate the memory for the matrices by hand, ensuring it's contiguous, and build the pointer structure yourself?
Also, does the dim() method have any extra complexity? I would declare it inline, too.
来源：https://stackoverflow.com/questions/4300663/how-to-speed-up-matrix-multiplication-in-c