Android 2.2 wifi hotspot API

冷暖自知 提交于 2019-12-28 01:42:51

问题


What is the API call I need to make in Android 2.2 (Froyo) to create a Wifi hotspot (as seen in the Tethering and Portable Hotspot settings item).


回答1:


You can call

private boolean setWifiApEnabled(WifiConfiguration wifiConfig, boolean enabled);

using reflection :)

after getting the WifiManager use the reflection to get the WifiManager declared methods, look for this method name setWifiApEnabled and invoke it through the WifiManager object

These API are marked as @hide, so currently you cannot use them directly, but they appear on the AIDL for the WifiManager so their are accessible!

An example can be:

WifiManager wifi = (WifiManager) getSystemService(Context.WIFI_SERVICE);
Method[] wmMethods = wifi.getClass().getDeclaredMethods();
for(Method method: wmMethods){
  if(method.getName().equals("setWifiApEnabled")){
    WifiConfiguration netConfig = new WifiConfiguration();
    netConfig.SSID = "\"PROVAAP\"";
    netConfig.allowedAuthAlgorithms.set(WifiConfiguration.AuthAlgorithm.OPEN);
    netConfig.allowedProtocols.set(WifiConfiguration.Protocol.RSN);
    netConfig.allowedProtocols.set(WifiConfiguration.Protocol.WPA);
    netConfig.allowedKeyManagement.set(WifiConfiguration.KeyMgmt.WPA_PSK);    netConfig.allowedPairwiseCiphers.set(WifiConfiguration.PairwiseCipher.CCMP);
    netConfig.allowedPairwiseCiphers.set(WifiConfiguration.PairwiseCipher.TKIP);
    netConfig.allowedGroupCiphers.set(WifiConfiguration.GroupCipher.CCMP);
    netConfig.allowedGroupCiphers.set(WifiConfiguration.GroupCipher.TKIP);  

    try {
      method.invoke(wifi, netConfig,true);
    } catch (IllegalArgumentException e) {
      e.printStackTrace();
    } catch (IllegalAccessException e) {
      e.printStackTrace();
    } catch (InvocationTargetException e) {
      e.printStackTrace();
    }
  }
}

It works but I cannot change the current configuration with my own, and getting the current WifiConfiguration of an active AP drive me to an empty configuration.Why?




回答2:


this works on API 8 and above. I use a heavily different version then this below (or above), and was running into the same issue markov00 ran into; not being able to load the default WifiConfiguration for the portable Wi-Fi AP. I found a solution elsewhere.

If you like the solution, it would be nice if this was accepted as an answer

WifiManager wifi    = (WifiManager) getSystemService(Context.WIFI_SERVICE);
Method[] wmMethods  = wifi.getClass().getDeclaredMethods();

for (Method method: wmMethods){
    if (method.getName().equals("setWifiApEnabled")){
        try {
            // just nullify WifiConfiguration to load the default configuration ;)
            method.invoke(wifi, null, true);
        } catch (IllegalArgumentException e){
            e.printStackTrace();
        } catch (IllegalAccessException e){
            e.printStackTrace();
        } catch (InvocationTargetException e){
            e.printStackTrace();
        }
    }
}



回答3:


There does not appear to be an API call to create a WiFi hotspot -- sorry!



来源:https://stackoverflow.com/questions/3023226/android-2-2-wifi-hotspot-api

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!