问题
What is the API call I need to make in Android 2.2 (Froyo) to create a Wifi hotspot (as seen in the Tethering and Portable Hotspot settings item).
回答1:
You can call
private boolean setWifiApEnabled(WifiConfiguration wifiConfig, boolean enabled);
using reflection :)
after getting the WifiManager
use the reflection to get the WifiManager
declared methods, look for this method name setWifiApEnabled
and invoke it through the WifiManager
object
These API are marked as @hide, so currently you cannot use them directly, but they appear on the AIDL for the WifiManager so their are accessible!
An example can be:
WifiManager wifi = (WifiManager) getSystemService(Context.WIFI_SERVICE);
Method[] wmMethods = wifi.getClass().getDeclaredMethods();
for(Method method: wmMethods){
if(method.getName().equals("setWifiApEnabled")){
WifiConfiguration netConfig = new WifiConfiguration();
netConfig.SSID = "\"PROVAAP\"";
netConfig.allowedAuthAlgorithms.set(WifiConfiguration.AuthAlgorithm.OPEN);
netConfig.allowedProtocols.set(WifiConfiguration.Protocol.RSN);
netConfig.allowedProtocols.set(WifiConfiguration.Protocol.WPA);
netConfig.allowedKeyManagement.set(WifiConfiguration.KeyMgmt.WPA_PSK); netConfig.allowedPairwiseCiphers.set(WifiConfiguration.PairwiseCipher.CCMP);
netConfig.allowedPairwiseCiphers.set(WifiConfiguration.PairwiseCipher.TKIP);
netConfig.allowedGroupCiphers.set(WifiConfiguration.GroupCipher.CCMP);
netConfig.allowedGroupCiphers.set(WifiConfiguration.GroupCipher.TKIP);
try {
method.invoke(wifi, netConfig,true);
} catch (IllegalArgumentException e) {
e.printStackTrace();
} catch (IllegalAccessException e) {
e.printStackTrace();
} catch (InvocationTargetException e) {
e.printStackTrace();
}
}
}
It works but I cannot change the current configuration with my own, and getting the current WifiConfiguration of an active AP drive me to an empty configuration.Why?
回答2:
this works on API 8 and above. I use a heavily different version then this below (or above), and was running into the same issue markov00 ran into; not being able to load the default WifiConfiguration for the portable Wi-Fi AP. I found a solution elsewhere.
If you like the solution, it would be nice if this was accepted as an answer
WifiManager wifi = (WifiManager) getSystemService(Context.WIFI_SERVICE);
Method[] wmMethods = wifi.getClass().getDeclaredMethods();
for (Method method: wmMethods){
if (method.getName().equals("setWifiApEnabled")){
try {
// just nullify WifiConfiguration to load the default configuration ;)
method.invoke(wifi, null, true);
} catch (IllegalArgumentException e){
e.printStackTrace();
} catch (IllegalAccessException e){
e.printStackTrace();
} catch (InvocationTargetException e){
e.printStackTrace();
}
}
}
回答3:
There does not appear to be an API call to create a WiFi hotspot -- sorry!
来源:https://stackoverflow.com/questions/3023226/android-2-2-wifi-hotspot-api