问题
I'm receiving this error when I am using an attached long press gesture to get a modal view to come up using the following code:
// Long press to go to settings for one
- (void)longPressOne:(UILongPressGestureRecognizer*)gesture {
[self performSegueWithIdentifier:@"buttonOne" sender:self];
}
// Long press to go to settings for two
- (void)longPressTwo:(UILongPressGestureRecognizer*)gesture {
[self performSegueWithIdentifier:@"buttonTwo" sender:self];
}
- (void)viewDidLoad {
// Add gesture to buttonOne
UILongPressGestureRecognizer *longPressOne = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(longPressOne:)];
[self.buttonOne addGestureRecognizer:longPressOne];
// Add gesture to buttonTwo
UILongPressGestureRecognizer *longPressTwo = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(longPressTwo:)];
[self.buttonTwo addGestureRecognizer:longPressTwo];
}
The modal segue is hitched up on the storyboard from the viewcontroller to the destination view. I know there are reports of this problem when there are multiple segues on the storyboard, but I just have the one as I can't create a segue from the button for a long press on Storyboard.
Any idea why this is happening?
回答1:
I have fixed this by altering the code for handling the gestures, as below:
// Long press to go to settings for one
- (void)longPressOne:(UILongPressGestureRecognizer*)gesture {
if (gesture.state == UIGestureRecognizerStateBegan)
{
[self performSegueWithIdentifier:@"buttonOne" sender:self];
}
}
// Long press to go to settings for two
- (void)longPressTwo:(UILongPressGestureRecognizer*)gesture {
if (gesture.state == UIGestureRecognizerStateBegan)
{
[self performSegueWithIdentifier:@"buttonTwo" sender:self];
}
}
This seems to fix the problem.
来源:https://stackoverflow.com/questions/25826814/warning-attempt-to-present-whose-view-is-not-in-the-window-hierarchy