Python: ipaddress.AddressValueError: At least 3 parts expected

问题

An attribute of ipaddress.IPv4Network can be used to check if any IP address is reserved.

In IPython:

In [52]: IPv4Address(u'169.254.255.1').is_private
Out[52]: False

Yet if I try the exact same thing in a function:

import ipaddress
def isPrivateIp(ip):
    unicoded = unicode(ip)
    if ipaddress.IPv4Network(unicoded).is_private or ipaddress.IPv6Network(unicoded).is_private:
        return True
    else:
        return False

print isPrivateIp(r'169.254.255.1')

I get:

  File "isPrivateIP.py", line 13, in <module>
    print isPrivateIp(ur'169.254.255.1')
  File "isPrivateIP.py", line 7, in isPrivateIp
    if ipaddress.IPv4Network(unicoded).is_private or ipaddress.IPv6Network(unicoded).is_private:
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/ipaddress.py", line 2119, in __init__
    self.network_address = IPv6Address(self._ip_int_from_string(addr[0]))
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/ipaddress.py", line 1584, in _ip_int_from_string
    raise AddressValueError(msg)
ipaddress.AddressValueError: At least 3 parts expected in u'169.254.255.1'

Why is this the case?

Note: In python 2, ip addresses must be passed to ipaddress functions as unicode objects, hence calling unicode() on the string input ip.

回答1:

The expected input for ipaddress.IPv6Network() is different than ipaddress.IPv4Network(). If you remove or ipaddress.IPv6Network(unicoded).is_private from your code it works fine. You can read more from here.

来源：https://stackoverflow.com/questions/30996001/python-ipaddress-addressvalueerror-at-least-3-parts-expected

标签

python

string

unicode

ip-address