问题
My indicator and value objects have composite keys that map to each other is there an efficient way to aggregate the values into the indicator object?
Given an "empty" indicator dataframe:
indicator <- data.frame(Id1=c(1,1,2,2,3,3,4,4), Id2=c(10,11,10,12,10,12,10,12),Ind_A=rep(0,8),Ind_B=rep(0,8))
Id1 Id2 Ind_A Ind_B
1 1 10 0 0
2 1 11 0 0
3 2 10 0 0
4 2 12 0 0
5 3 10 0 0
6 3 12 0 0
7 4 10 0 0
8 4 12 0 0
and a dataframe of values:
values <- data.frame(Id1=c(1,1,1,2,2,3,3,4,4,4),Id2=c(10,10,11,10,12,10,12,10,10,12),Indicators=c('Ind_A','Ind_B','Ind_A','Ind_B','Ind_A','Ind_A','Ind_A','Ind_A','Ind_B','Ind_A'));
Id1 Id2 Indicators
1 1 10 Ind_A
2 1 10 Ind_B
3 1 11 Ind_A
4 2 10 Ind_B
5 2 12 Ind_A
6 3 10 Ind_A
7 3 12 Ind_A
8 4 10 Ind_A
9 4 10 Ind_B
10 4 12 Ind_A
I want to end up with:
Id1 Id2 Ind_A Ind_B
1 10 1 1
1 11 1 0
2 10 0 1
2 12 1 0
3 10 1 0
3 12 1 0
4 10 1 1
4 12 1 0
回答1:
You could use dcast
to convert the "values" dataset from 'long' to 'wide' format.
library(reshape2)
dcast(values, Id1+Id2~Indicators, value.var='Indicators', length)
# Id1 Id2 Ind_A Ind_B
#1 1 10 1 1
#2 1 11 1 0
#3 2 10 0 1
#4 2 12 1 0
#5 3 10 1 0
#6 3 12 1 0
#7 4 10 1 1
#8 4 12 1 0
As showed above, you may not need to create a second dataset, but if you need to change the values in one dataset based on the value in other,
indicator$Ind_A <- (do.call(paste, c(indicator[1:2], 'Ind_A')) %in%
do.call(paste, values))+0L
indicator$Ind_B <- (do.call(paste, c(indicator[1:2], 'Ind_B')) %in%
do.call(paste, values))+0L
来源:https://stackoverflow.com/questions/30243920/an-efficient-way-to-indicate-multiple-indicator-variables-per-row-with-composite