MarshalJSON a type with an embedded type ends up as {} instead of the value

余生颓废 提交于 2019-12-24 10:56:17

问题


To interact with swagger, I needed to make a custom BigInt struct which does nothing more than wrap around go's big.Int.

type BigInt struct {
    big.Int
}

...
type SpendTx struct {
    SenderID    string       `json:"sender_id,omitempty"`
    RecipientID string       `json:"recipient_id,omitempty"`
    Amount      utils.BigInt `json:"amount,omitempty"`
    Fee         utils.BigInt `json:"fee,omitempty"`
    Payload     string       `json:"payload,omitempty"`
    TTL         uint64       `json:"ttl,omitempty"`
    Nonce       uint64       `json:"nonce,omitempty"`
}

func (t SpendTx) JSON() (output []byte, err error) {
    return json.Marshal(t)
}

I'd expect SpendTx.JSON() to eventually call big.Int.MarshalJSON(), which would return 0. Instead, I got this output:

{"sender_id":"alice","recipient_id":"bob","amount":{},"fee":{},"payload":"Hello World","ttl":10,"nonce":1}

But what I really want is this:

{"sender_id":"alice","recipient_id":"bob","amount":10,"fee":10,"payload":"Hello World","ttl":10,"nonce":1}

And I had to add this bit of code to BigInt to do it:

func (b BigInt) MarshalJSON() ([]byte, error) {
    return b.Int.MarshalJSON()
}

But according to Effective Go's section on embedding structs, this shouldn't be necessary at all. Why is big.Int appearing as as {}?


回答1:


big.Int implements a custom JSON marshaler (json.Marshaler), see Int.MarshalJSON(). But this method has pointer receiver, so it is only used / called, if you have a pointer value: *big.Int.

And you embed a non-pointer value, so this custom marshaler is not called, and since big.Int is a struct with unexported fields, you will see an empty JSON object in the output: {}.

To make it work, you should use a pointer to your type, e.g.:

Amount      *utils.BigInt `json:"amount,omitempty"`
Fee         *utils.BigInt `json:"fee,omitempty"`

Example using it:

s := SpendTx{
    SenderID:    "alice",
    RecipientID: "bob",
    Amount:      &utils.BigInt{},
    Fee:         &utils.BigInt{},
}
data, err := s.JSON()
fmt.Println(string(data), err)

Then output will be for example (try it on the Go Playground):

{"sender_id":"alice","recipient_id":"bob","amount":0,"fee":0} <nil>

Another option is to use the non-pointer utils.BigInt, but then utils.BigInt should embed a pointer type:

type BigInt struct {
    *big.Int
}

type SpendTx struct {
    Amount      utils.BigInt `json:"amount,omitempty"`
    Fee         utils.BigInt `json:"fee,omitempty"`
}

And then using it:

s := SpendTx{
    SenderID:    "alice",
    RecipientID: "bob",
    Amount:      utils.BigInt{new(big.Int)},
    Fee:         utils.BigInt{new(big.Int)},
}
data, err := s.JSON()
fmt.Println(string(data), err)

And output will be again (try it on the Go Playground):

{"sender_id":"alice","recipient_id":"bob","amount":0,"fee":0} <nil>


来源:https://stackoverflow.com/questions/55337900/marshaljson-a-type-with-an-embedded-type-ends-up-as-instead-of-the-value

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