MAPE metric at h2O

问题

What is correct way to implement MAPE under h2o framework?

I am interested to convert below function to h2o concept

def mape(a, b): 
    mask = a <> 0
    return (np.fabs(a - b)/a)[mask].mean()

回答1:

import h2o
h2o.init()
df = h2o.create_frame(rows=100, cols=2, missing_fraction=0, integer_fraction=1, integer_range=5)
print(df)

def mape(a, b):
    mask = a != 0
    return (abs(a-b)/a)[mask].mean()

mape(df[0],df[1])

来源：https://stackoverflow.com/questions/43103022/mape-metric-at-h2o