How to fix error in my pyqt programm (first argument of unbound method must have type 'QDialog') ?

问题

After typing 1, both as login and password, a new window should appear, but it gives an error.

It used to work fine before I made some changes to code, and I don't know what exactly causes it.

 # -*- coding: utf-8 -*-
from PyQt4 import QtGui, QtCore
import sys

app = QtGui.QApplication(sys.argv)
login = QtGui.QDialog()

login.setWindowTitle('login')
login.resize(100, 100)

login_form = QtGui.QFormLayout()

row1 = QtGui.QHBoxLayout()
user_input = QtGui.QLineEdit()
row1.addWidget(user_input)
login_form.addRow('user', row1)
row2 = QtGui.QHBoxLayout()
pwd_input = QtGui.QLineEdit()
row2.addWidget(pwd_input)
login_form.addRow('pwd', row2)
row3 = QtGui.QHBoxLayout()
login_btn = QtGui.QPushButton('LOGIN')
exit_btn = QtGui.QPushButton('EXIT')
row3.addWidget(login_btn)
row3.addWidget(exit_btn)
login_form.addRow(row3)

login.setLayout(login_form)

def handleLogin():
    if (user_input.text() == '1' and
        pwd_input.text() == '1'):
        QtGui.QDialog.accept()  
    else:
        QtGui.QMessageBox.warning(login, 'Error', 'Bad user or password',
                                buttons = QtGui.QMessageBox.Close,
                                defaultButton = QtGui.QMessageBox.Close)
QtCore.QObject.connect(login_btn, QtCore.SIGNAL('clicked()'), handleLogin)

if login.exec_() == QtGui.QDialog.Accepted:
    window = QtGui.QWidget()
    window.show()
    sys.exit(app.exec_())

回答1:

The error happens because you are attepting to call a method via the class, rather than the instance. Try this instead:

def handleLogin():
    if (user_input.text() == '1' and pwd_input.text() == '1'):
        login.accept()  

来源：https://stackoverflow.com/questions/40309352/how-to-fix-error-in-my-pyqt-programm-first-argument-of-unbound-method-must-have