问题
I'm using the getclosest command to find a vertex.
ForceVertex1 = hatInstance.vertices.getClosest(coordinates=((x,y,z,))
This is a dictionary object with Key 0 and two values (hatInstance.vertices[1] and the coordinates of the vertex) The specific output:
{0: (mdb.models['EXP-100'].rootAssembly.instances['hatInstance-100'].vertices[1], (62.5242172081597, 101.192447407436, 325.0))}
Whenever I try to create a set, the vertex isn't accepted
mainAssembly.Set(vertices=ForceVertex1[0][0],name='LoadSet1')
I also tried a different way:
tolerance = 1.0e-3
vertex = []
for vertex in hatInstance.vertices:
x = vertex.pointOn[0][0]
print x
y = vertex.pointOn[0][1]
print y
z = vertex.pointOn[0][2]
print z
break
if (abs(x-xTarget)) < tolerance and abs(y-yTarget) < tolerance and abs(z-zTarget) < tolerance):
vertex.append(hatInstance.vertices[vertex.index:vertex.index+1])
xTarget etc being my coordinates, despite this I still don't get a vertex object
回答1:
For those struggeling with this, I solved it.
Don't use the getClosest command as it returns a dictionary object despite the manual recommending this. I couldn't convert this dictionary object, specifically a key and a value within to a standalone object (vertex)
Instead use Instance.vertices.getByBoundingSphere(center=,radius=) The center is basically a tuple of the coordinates and the radius is the tolerance. This returns an array of vertices
回答2:
If you want the geometrical object you just have to access the dictionary. One way to do it is:
ForceVertex1 = hatInstance.vertices.getClosest(coordinates=((x,y,z,))[0][0]
This will return the vertices object only, which you can assign to a set or whatever.
来源:https://stackoverflow.com/questions/39030382/abaqus-python-getclosest-command