Extract only the body part of incoming emails using bash

问题

I use offlineimap to fetch the mails into a Maildir folder.

I want to automatically parse all new incoming emails in a Maildir folder and send only the "from", "subject" and "body" as an instant message somewhere else.

So I try to process all mails with

MPATH=~/Mail 

if [ -n "$(ls "$MPATH/INBOX/new/")" ]; then 
    for f in "$MPATH/INBOX/new/"*; do  
        SUB="$(cat "$f"|grep '^Subject' | head -n1 | sed "s/Subject: //g")"                                                                                       
        FROM="$(cat "$f" | grep '^From' | head -n1 | head -n 1|sed "s/From: //g")"                                                                                
        BODY="$(cat "$f"|sed -e '1,/Content-Transfer-Encoding/d')"
        MESS="$FROM: $SUB$BODY"

        echo $f 
        echo "$MESS" 
        mv "$f" "$MPATH/INBOX/cur/" 
    done 
fi

This already works fine for some simple emails, but how do I get rid of everything that is not the plain body, like signatures, attachements,...?

回答1:

As answered in the comments, formail from the procmail package seems to do the job nicely:

$ sudo apt-get install procmail

$ cat test.eml | formail -x To
 test@atleticomadridhistory.com

$ cat test.eml | formail -x Subject
 hello

$ cat test.eml | formail -x Content
 multipart/alternative; boundary="f403043eea78e8658a0554677278"

Credits: @glennjackman

来源：https://stackoverflow.com/questions/36168224/extract-only-the-body-part-of-incoming-emails-using-bash