问题
OK I have this function (I got as the answer to this question) that merges an array like so:
Functions
function readArray( $arr, $k, $default = 0 ) {
return isset( $arr[$k] ) ? $arr[$k] : $default ;
}
function merge( $arr1, $arr2 ) {
$result = array() ;
foreach( $arr1 as $k => $v ) {
if( is_numeric( $v ) ) {
$result[$k] = (int)$v + (int) readArray( $arr2, $k ) ;
} else {
$result[$k] = merge( $v, readArray($arr2, $k, array()) ) ;
}
}
return $result ;
}
Usage
$basketA = array( "fruit" => array(), "drink" => array() ) ;
$basketA['fruit']['apple'] = 1;
$basketA['fruit']['orange'] = 2;
$basketA['fruit']['banana'] = 3;
$basketA['drink']['soda'] = 4;
$basketA['drink']['milk'] = 5;
$basketB = array( "fruit" => array(), "drink" => array() ) ;
$basketB['fruit']['apple'] = 2;
$basketB['fruit']['orange'] = 2;
$basketB['fruit']['banana'] = 2;
$basketB['drink']['soda'] = 2;
$basketB['drink']['milk'] = 2;
$basketC = merge( $basketA, $basketB ) ;
print_r( $basketC ) ;
Output
Array
(
[fruit] => Array
(
[apple] => 3
[orange] => 4
[banana] => 5
)
[drink] => Array
(
[soda] => 6
[milk] => 7
)
)
OK this works with 1 flaw I cannot figure out how to fix: if $arr1 is missing something that $arr2 has, it should just use the value from $arr2 but instead omits it all together:
Example
$basketA = array( "fruit" => array(), "drink" => array() ) ;
$basketA['fruit']['apple'] = 1;
$basketA['fruit']['orange'] = 2;
$basketA['fruit']['banana'] = 3;
$basketA['drink']['milk'] = 5;
$basketB = array( "fruit" => array(), "drink" => array() ) ;
$basketB['fruit']['apple'] = 2;
$basketB['fruit']['orange'] = 2;
$basketB['fruit']['banana'] = 2;
$basketB['drink']['soda'] = 2;
$basketB['drink']['milk'] = 2;
$basketC = merge( $basketA, $basketB ) ;
print_r( $basketC ) ;
Output
Array
(
[fruit] => Array
(
[apple] => 3
[orange] => 4
[banana] => 5
)
[drink] => Array
(
[milk] => 7
)
)
Notice how [soda] is not in the new array because the first array did not have it.
How can I fix this???
Thanks!!!
回答1:
Quick fix, change the merge()
function to look like this:
function merge( $arr1, $arr2 ) {
$result = array() ;
foreach( $arr1 as $k => $v ) {
if( is_numeric( $v ) ) {
$result[$k] = (int)$v + (int) readArray( $arr2, $k ) ;
} else {
$result[$k] = merge( $v, readArray($arr2, $k, array()) ) ;
}
}
foreach( $arr2 as $k => $v ) {
if( is_numeric( $v ) ) {
$result[$k] = (int)$v + (int) readArray( $arr1, $k ) ;
} else {
$result[$k] = merge( $v, readArray($arr1, $k, array()) ) ;
}
}
return $result ;
}
Output:
Array
(
[fruit] => Array
(
[apple] => 3
[orange] => 4
[banana] => 5
)
[drink] => Array
(
[soda] => 2
[milk] => 7
)
)
It's also worth noticing that array_merge_recursive()
alone does almost the same:
$basketC = array_merge_recursive($basketA, $basketB);
Output:
Array
(
[fruit] => Array
(
[apple] => Array
(
[0] => 1
[1] => 2
)
[orange] => Array
(
[0] => 2
[1] => 2
)
[banana] => Array
(
[0] => 3
[1] => 2
)
)
[drink] => Array
(
[milk] => Array
(
[0] => 5
[1] => 2
)
[soda] => 2
)
)
So if you wanted to know how many oranges are in $basketC
, you would just have to do:
array_sum($basketC['fruit']['orange']); // 4
This way you don't need to use any hackish, slow and unproved custom function.
来源:https://stackoverflow.com/questions/2119647/php-problem-merging-arrays