How to configure gcc to use -no-pie by default?

问题

I want to compile the following program on Linux:

    .global _start
    .text
_start:
    mov $1,   %rax
    mov $1,   %rdi
    mov $msg, %rsi
    mov $13,  %rdx
    syscall
    mov $60,  %rax
    xor %rdi, %rdi
    syscall
msg:
    .ascii "Hello World!\n"

However, it gives me the following linker error:

$ gcc -nostdlib hello.s
/usr/bin/ld: /tmp/ccMNQrOF.o: relocation R_X86_64_32S against `.text' can not be used when making a shared object; recompile with -fPIC
/usr/bin/ld: final link failed: Nonrepresentable section on output
collect2: error: ld returned 1 exit status

I figured that the reason it doesn't work is because gcc is using -pie to generate a shared object by default. Thus, using -no-pie fixes it:

$ gcc -no-pie -nostdlib hello.s
$ ./a.out
Hello World!

How do I configure gcc to use -no-pie by default? I'm using Arch Linux.

回答1:

I guess just don't configure gcc with --enable-default-pie.

See this blog post: http://nanxiao.me/en/gccs-enable-enable-default-pie-option-make-you-stuck-at-relocation-r_x86_64_32s-against-error/, and Arch patch that enabled pie by default: https://git.archlinux.org/svntogit/packages.git/commit/trunk?h=packages/gcc&id=5936710c764016ce306f9cb975056e5b7605a65b.

来源：https://stackoverflow.com/questions/49101265/how-to-configure-gcc-to-use-no-pie-by-default