look for a specific filetype in a directory in php and send it to a different directory after conversion

问题

I have a directory in which there is a mp4 file (including other files as well) which I want to convert into mp3 and then send it to different directory. I have used the following command line command to covert into mp3 and its working perfectly fine.

ffmpeg -i 36031P.mp4 -map 0:2 -ac 1 floor_english.mp3

mp4 file is inside in_folder. Using ffmpeg, I want to convert mp4 file into mp3 and send it to out_folder.

<?php
$dir    = 'in_folder';
$files1 = scandir($dir);
print_r($files1);    /* It lists all the files in a directory including mp4 file*/
?>

print_r($files1) lists all the file in a directory including mp4file.

Problem Statement:

I am wondering what php code I need to write so that it looks for only mp4 file inside the directory and send it to different directory (let say out_folder) after converting into mp3.

The pictorial representation of what I want:

回答1:

In think it is what you want :

<?php
$dir    = 'in_folder';
$files1 = scandir($dir);
print_r($files1);    /* It lists all the files in a directory including mp4 file*/

$destination = 'your new destination';

foreach($files1 as $f)
{
  $parts = pathinfo($f);
  if ($parts['extension'] = 'mp3';
  {
    // copy($f, $destination. DS . $parts['filename']. '.' . $parts['extension']);
    rename($f, $destination. DS . $parts['filename']. '.mp3');
  }
}
?>

Documentation pathinfo

Edit with convertion :

I think you can directly export your mp3 like this

foreach($files1 as $f)
{
  $parts = pathinfo($f);
  if ($parts['extension'] = 'mp4';
  {
    // $result : the last line of the command output on success, and FALSE on failure. Optional.
    system('ffmpeg -i '.$f.' -map 0:2 -ac 1 '.$destination.DS. $parts['filename'].'.mp3', $result);
  }

  // See: https://www.php.net/manual/en/function.system.php
  if ($result === false) {
    // Do something if failed
    // log for example
  } else {
    // command completed with code : $result
    // 0 by convention for exit with success EXIT_SUCCESS
    // 1 by convention for exit with error EXIT_ERROR
    // https://stackoverflow.com/questions/12199216/how-to-tell-if-ffmpeg-errored-or-not
  }
}

Documentation system

or do a first loop too convert mp4, and a second loop to copy mp3

Edit all in one :

foreach($files1 as $f)
{
  $parts = pathinfo($f);

  switch(strtolower($parts['extension']))
  {
    case 'mp4' :
      // $result : the last line of the command output on success, and FALSE on failure. Optional.
      system('ffmpeg -i '.$f.' -map 0:2 -ac 1 '.$destination.DS. $parts['filename'].'.mp3', $result);

      // See: https://www.php.net/manual/en/function.system.php
      if ($result === false) {
        // Do something if failed
        // log for example
      } else {
        // command completed with code : $result
        // 0 by convention for exit with success EXIT_SUCCESS
        // 1 by convention for exit with error EXIT_ERROR
        // https://stackoverflow.com/questions/12199216/how-to-tell-if-ffmpeg-errored-or-not
      }
      break;

    case 'mp3' :
      // copy($f, $destination. DS . $parts['filename']. '.' . $parts['extension']);
      rename($f, $destination.DS.$parts['filename'].'.mp3');
      break;  
  }
}

Edit 1 : correction strtolower($parts['extension']) to check the extension of the file none case-sensitive.

or like this :

strtolower(pathinfo("/path/file.mP4", PATHINFO_EXTENSION)) == ".mp4"

There is no need to use preg_match and regexp because pathinfo is a pre-made function to do the job and it works fine unless you use double named extension like .tar.gz for example.

regular-expression-to-detect-a-file-extension

Edit 2 : Use rename instead of copy to move mp3.

回答2:

I feel this could all be a bit more robust and shorter.

<?php

// the folder to get MP4's from, recursively
$src_dir = 'folder/a';
// the destination to put MP3's in.
$dst_dir = 'folder/b';

// An iterator ('reader') that takes all files in src
$files = new RecursiveIteratorIterator(
    new RecursiveDirectoryIterator($src_dir)
);

// A filter, that only leaves entries ending with .mp4, case-insensitive.
$videos = new RegexIterator($files, '/^.+\.mp4$/i', RecursiveRegexIterator::MATCH));

// Then, for each element in videos, convert to MP3
foreach ($videos as $video) {
    $src = $video->getPathname();
    // The destination is the basename without 'mp4', with 'mp3' appended.
    $dst = $dst_dir.'/'.$video->getBaseName($video->getExtension()).'mp3';

    system("ffmpeg -i $src -map 0:2 -ac 1 $dst");
}

You should take care that you don't allow 'user specified' names for files, but use your own (random) filenames. Avoid executing unvalidated user input at all cost!

回答3:

This will do it. I tested the solution and it works. I had to make one parameter change for the ffmpeg command. On my machine, it was throwing an error for the mapping. I added a question mark after the mapping to ignore the error.

The code assumes the following folder structure:

<?php

  error_reporting(E_ALL);

  $in_folder = sprintf("%s/mp4", __DIR__);
  $out_folder = sprintf("%s/mp3", __DIR__);

  if(!file_exists($in_folder)){
    mkdir($in_folder);
  }

  if(!file_exists($out_folder)){
    mkdir($out_folder);
  }

  $items = scandir($in_folder);
  foreach($items as $item){
    if(preg_match('/^.*\.mp4$/', $item)){
      $file_name = str_replace(".mp4", "", $item);
      $in_file = sprintf("%s/%s.mp4", $in_folder, $file_name);
      $out_file = sprintf("%s/%s.mp4", $out_folder, $file_name);
      if(file_exists($out_file)){
        unlink($out_file);
      }
      $cmd = sprintf("ffmpeg -i %s -map 0:2? -ac 1 %s", $in_file, $out_file);
      print "$cmd\n";
      exec($cmd);
    }
  }

?>

来源：https://stackoverflow.com/questions/56094984/look-for-a-specific-filetype-in-a-directory-in-php-and-send-it-to-a-different-di

标签

php

ffmpeg

mp3

mp4

scandir