Simply retrieving all records from a store

问题

Instead of retrieving a single row of data from my store, how can I modify the following code to retrieve all records?

var store = Ext.data.StoreManager.lookup('MyStore');
        store.setProxy({
            type: 'pagingmemory',
            data: store.getAt(0)
          });
        store.load();

Any thoughts?

回答1:

You can use store.getRange() or you can use store.data.items. For the getRange() call, passing no parameters just defaults to 0 and the last record in the store.

回答2:

I think this is not complete true, since getRange() will retrieve all the records from a store first page.

If your store has pages of 50 records per page, then store.getRange() will give you only the first 50 records.

回答3:

store.getRange()

will only retrieve the page currently worked on if the grid is not defined to have a buffered store. Store can be set as buffered by:

(buffered: true)

But that will decrease the performance since the whole page will be buffered even if a single page will be retrieved.

The most efficient way that comes to my mind is:

    var pageSize = store.pageSize // will return the page size.
    var totalCount = store.totalCount // This will return total no of items

    for (var i=0; i<(totalCount/pageSize)+1;i++) {
         store.loadPage(i) // this will set the current page of the store to i variable.  
         ....
         ....
    }

回答4:

This will reload the store with all records:

store.load({start:0, limit: store.totalCount, page:1});

Take all records from store:

var records = store.getRange();`

来源：https://stackoverflow.com/questions/18340026/simply-retrieving-all-records-from-a-store

标签

javascript

extjs

rows

store