What does the “double” do in ceil(double)?

问题

I have a number (let's say, 34), and I want to find its next multiple of ten. I can do this by:

1. Dividing the number by 10
2. Rounding it up to a whole number
3. Multiplying by 10.

After a bit of research, I discovered that this is the code for that in Objective C:

int number = 34;
int roundedNumber = ceil((double)number/10)*10;

My question is: what is the (double) for, and why does removing (double) cause it to round down instead of up?

I understand from googling that changes the float format to "double precision" but, to be honest, this is way too complicated for me. Can anyone provide a simple explanation of what it is doing?

回答1:

If you don't have the cast the following happens (if number is 34).

1. Using integer arithmetic, number/10 is number/10 rounded down, ie 3.
2. ceil(3) = 3
3. 3*10 = 30

If you have the cast, the following happens:

1. (double)number = 34.0
2. 34.0 / 10 = 3.4
3. ceil(3.4) = 4.0
4. 4.0*10 = 40

The important thing to realise is Integer division always rounds towards 0.

回答2:

It casts number as a double so that float division is performed instead of integer division. Compare 1/2 versus 1.0/2.

来源：https://stackoverflow.com/questions/5976832/what-does-the-double-do-in-ceildouble