问题
this is the representation of my models:
class B(models.Model):
"""I'm a dummy model, so doesn't pay atention of what I do"""
name = models.CharField(max_length=250)
class A(models.Model):
name = models.CharField(max_length=250)
many_b = models.ManyToManyField(B)
Now, suppose I have a list of B
objects. And a single A
object that will be related to that B
s. Something like this:
a = A.objects.get(id=1)
list_of_b = [B<name='B1'>,B<name='B2'>,B<name='B3'>,]
The way I relate them now is this:
for b_object in list_of_b:
a.many_b.add(b_object)
Is there any way to add all the B objects in a single transaction? Maybe in a single method, like:
a.many_b.addList(b) #This doesn't exist
回答1:
From the docs:
>>> john = Author.objects.create(name="John")
>>> paul = Author.objects.create(name="Paul")
>>> george = Author.objects.create(name="George")
>>> ringo = Author.objects.create(name="Ringo")
>>> entry.authors.add(john, paul, george, ringo)
So if you have a list, use argument expansion:
a.many_b.add(*list_of_b)
回答2:
I guess what you want is a kind of bulk insert right?
As far as I know this is just available in the Django TRUNK not in 1.3!
check it out some tutorial: http://www.caktusgroup.com/blog/2011/09/20/bulk-inserts-django/
来源:https://stackoverflow.com/questions/8343620/django-saving-multiple-manytomany-fields-within-a-transaction