How to stop a goroutine

问题

I have a goroutine that calls a method, and passes returned value on a channel:

ch := make(chan int, 100)
go func(){
    for {
        ch <- do_stuff()
    }
}()

How do I stop such a goroutine?

回答1:

EDIT: I wrote this answer up in haste, before realizing that your question is about sending values to a chan inside a goroutine. The approach below can be used either with an additional chan as suggested above, or using the fact that the chan you have already is bi-directional, you can use just the one...

If your goroutine exists solely to process the items coming out of the chan, you can make use of the "close" builtin and the special receive form for channels.

That is, once you're done sending items on the chan, you close it. Then inside your goroutine you get an extra parameter to the receive operator that shows whether the channel has been closed.

Here is a complete example (the waitgroup is used to make sure that the process continues until the goroutine completes):

package main

import "sync"
func main() {
    var wg sync.WaitGroup
    wg.Add(1)

    ch := make(chan int)
    go func() {
        for {
            foo, ok := <- ch
            if !ok {
                println("done")
                wg.Done()
                return
            }
            println(foo)
        }
    }()
    ch <- 1
    ch <- 2
    ch <- 3
    close(ch)

    wg.Wait()
}

回答2:

Typically, you pass the goroutine a (possibly separate) signal channel. That signal channel is used to push a value into when you want the goroutine to stop. The goroutine polls that channel regularly. As soon as it detects a signal, it quits.

quit := make(chan bool)
go func() {
    for {
        select {
        case <- quit:
            return
        default:
            // Do other stuff
        }
    }
}()

// Do stuff

// Quit goroutine
quit <- true

回答3:

You can't kill a goroutine from outside. You can signal a goroutine to stop using a channel, but there's no handle on goroutines to do any sort of meta management. Goroutines are intended to cooperatively solve problems, so killing one that is misbehaving would almost never be an adequate response. If you want isolation for robustness, you probably want a process.

回答4:

Generally, you could create a channel and receive a stop signal in the goroutine.

There two way to create channel in this example.

channel
context. In the example I will demo context.WithCancel

The first demo, use channel:

package main

import "fmt"
import "time"

func do_stuff() int {
    return 1
}

func main() {

    ch := make(chan int, 100)
    done := make(chan struct{})
    go func() {
        for {
            select {
            case ch <- do_stuff():
            case <-done:
                close(ch)
                return
            }
            time.Sleep(100 * time.Millisecond)
        }
    }()

    go func() {
        time.Sleep(3 * time.Second)
        done <- struct{}{}
    }()

    for i := range ch {
        fmt.Println("receive value: ", i)
    }

    fmt.Println("finish")
}

The second demo, use context:

package main

import (
    "context"
    "fmt"
    "time"
)

func main() {
    forever := make(chan struct{})
    ctx, cancel := context.WithCancel(context.Background())

    go func(ctx context.Context) {
        for {
            select {
            case <-ctx.Done():  // if cancel() execute
                forever <- struct{}{}
                return
            default:
                fmt.Println("for loop")
            }

            time.Sleep(500 * time.Millisecond)
        }
    }(ctx)

    go func() {
        time.Sleep(3 * time.Second)
        cancel()
    }()

    <-forever
    fmt.Println("finish")
}

回答5:

I know this answer has already been accepted, but I thought I'd throw my 2cents in. I like to use the tomb package. It's basically a suped up quit channel, but it does nice things like pass back any errors as well. The routine under control still has the responsibility of checking for remote kill signals. Afaik it's not possible to get an "id" of a goroutine and kill it if it's misbehaving (ie: stuck in an infinite loop).

Here's a simple example which I tested:

package main

import (
  "launchpad.net/tomb"
  "time"
  "fmt"
)

type Proc struct {
  Tomb tomb.Tomb
}

func (proc *Proc) Exec() {
  defer proc.Tomb.Done() // Must call only once
  for {
    select {
    case <-proc.Tomb.Dying():
      return
    default:
      time.Sleep(300 * time.Millisecond)
      fmt.Println("Loop the loop")
    }
  }
}

func main() {
  proc := &Proc{}
  go proc.Exec()
  time.Sleep(1 * time.Second)
  proc.Tomb.Kill(fmt.Errorf("Death from above"))
  err := proc.Tomb.Wait() // Will return the error that killed the proc
  fmt.Println(err)
}

The output should look like:

# Loop the loop
# Loop the loop
# Loop the loop
# Loop the loop
# Death from above

回答6:

Personally, I'd like to use range on a channel in a goroutine:

https://play.golang.org/p/qt48vvDu8cd

Dave has written a great post about this: http://dave.cheney.net/2013/04/30/curious-channels.

来源：https://stackoverflow.com/questions/6807590/how-to-stop-a-goroutine

标签

goroutine

channels