Conditionals on a chained deferred in jquery

问题

Let say I chained the $.Deferred like this.

$.each(data, function(k, v) {
    promise.then(function() {
        return $.post(...);
    }).then(function(data) {
        if(data)... // here is the conditions
        return $.post(...);
    }).then(function(data) {
        if(data)... // here is another condition
        return $.post(...);
    })
});

promise.done(function() {
    console.log("All Done!");
});

Am I doing it right? how do I prevent the next chain to execute if the condition return false, and where do I do this:

if(data){
   console.log('Success');
}

Can that code be in between those .thens?

回答1:

Joey, whether or not you are doing it right depends on the detail of what you are trying to achieve.

If you are trying to build one long .then() chain with a terminal .done(), where each .then()'s 'done' handler either :

calls an asynchronous process, or
transparently passes data on to the next .then() in the chain

then, the code should be of the following form :

var promise = ...;//An expression that returns a resolved or resolvable promise, to get the chain started.

$.each(data, function(k, v) {
    promise = promise.then(function() {//The `.then()` chain is built by assignment 
        if(data...) { return $.post(...); }
        else { return data; }//Transparent pass-through of `data`
    }).then(function(data) {
        if(data...) { return $.post(...); }
        else { return data; }//Transparent pass-through of `data`
    });
});

promise.done(function() {
    console.log("All Done!");
}).fail(function(jqXHR) {
    console.log("Incomplete - an ajax call failed");
});

If, however, you are trying to do the same but where each .then()'s 'done' handler either :

calls an asynchronous process, or
interrupts the .then() chain

then, the code should be of the following form :

var promise = ...;//An expression that returns a resolved or resolvable promise, to get the chain started.

$.each(data, function(k, v) {
    promise = promise.then(function(data) {
        if(data...) { return $.post(...); }
        else { return $.Deferred().reject(data).promise(); }//Force the chain to be interrupted
    }).then(function(data) {
        if(data...) { return $.post(...); }
        else { return $.Deferred().reject(data).promise(); }//Force the chain to be interrupted
    });
});

promise.done(function() {
    console.log("All Done!");
}).fail(function(obj) {//Note: `obj` may be a data object or an jqXHR object depending on what caused rejection.
    console.log("Incomplete - an ajax call failed or returned data determined that the then() chain should be interrupted");
});

回答2:

jQuery's then returns a new promise, which is monitored by the following chained then. Whatever is returned from the previous then is passed as the first argument of the next then.

promise.then(function() {
  return $.post(...);
}).then(function(data) {
  //we return false or some indicator that next shouldn't run
  if(!data) return false; 
  //else we return something
  else return $.post(...);
}).then(function(data) {
  //here we receive false, we return early, preventing further code from executing
  if(!data) return false;
  //otherwise, the following code runs
  return $.post(...);
})

来源：https://stackoverflow.com/questions/16351050/conditionals-on-a-chained-deferred-in-jquery

标签

javascript

jquery

ajax

chaining

deferred