问题
I am trying open & close accordion panes programatically. Here is the simplified version of my code. Even though I set the first pane's selected to false and and second pane's selected to true, only the first pane opens when it loads on the browser (FF3).
var accordionContainer = new dijit.layout.AccordionContainer().placeAt("test");
var accordPane = new dijit.layout.ContentPane({"title": "test", "content":"hello"});
var accordPane2 = new dijit.layout.ContentPane({"title": "test1", "content":"hello1"});
accordionContainer.addChild(accordPane);
accordionContainer.addChild(accordPane2, 1);
accordPane.startup();
accordPane2.startup();
//accordionContainer.selectChild(accordPane2);
accordionContainer.startup();
accordPane.selected = false;
accordPane2.selected = true;
回答1:
You can do it like this:
accordionContainer.selectChild( accordPane2 );
Assuming you are using dojo 1.3.
dijit.layout.AccordionContainer
is a subclass of dijit.layout.StackContainer
, which has selectChild
defined.
I set up a demo page where you can see this code in action
If you were calling selectChild
before startup
, that could cause the error you were seeing since the widget wasn't in a 'complete' state. (Sorry, missed the commneted out code before I posted original answer)
来源:https://stackoverflow.com/questions/1190157/whats-the-best-way-to-programatically-open-a-pane-inside-dijit-accordioncontaine