问题
so I have 2 apps running in the same project.
My files are structured as follows:
/project_codebase
/project
__init.py
settings.py
urls.py
wsgi.py
...
/app1
...
/app2
...
manage.py
So, I for some weird reason have a different name for my base directory (that is, it ends with codebase). Hopefully, that is not an issue.
In my settings.py, I have this:
INSTALLED_APPS = [
...
'app1',
'app2',
]
Ok, so in my models.py (from app2), I can easily import models from app1 with from app1.models import *
, however, when I use from app2.models import *
in my models.py (from app1), I get an ImportError.
Any solutions to this?
回答1:
This might be due to circular import issues. To avoid this you should load the model dynamically:
For recent versions of django (1.7+) use the application registry:
from django.apps import apps
MyModel1 = apps.get_model('app1', 'MyModel1')
For earlier django versions (<1.7):
from django.db.models.loading import get_model
MyModel1 = get_model('app1', 'MyModel1')
Note 1: If you want to define a ForeignKey relationship, there is no need for a separate import statement. Django has you covered on this:
If app1
is an installed app, you should define the ForeignKey relationship as follows:
# in app2.py
class MyModel2(models.Model):
mymodel1 = models.ForeignKey('app1.MyModel1')
Note 2: The get_model
only works if app1
is an installed app and MyModel1
is the model you want to import from app1
.
Note 3: Try to avoid wildcard import (from ... import *
), as this is bad practice.
回答2:
It's definitely a circular import.
But i think is what you need is to use models as some sort of RetationFields(ForeignKey
, ManyToManyField
or OneToOneField
) arguments. So you need to skip import and use as so:
# app1/models.py
class Model1(models.Model):
relation_field = models.ForeignKey('app2.Model2')
From docs:
If you need to create a relationship on a model that has not yet been defined, you can use the name of the model, rather than the model object itself
To refer to models defined in another application, you can explicitly specify a model with the full application label
Just put str
object as first argument to relation fields that leeds to <app_name>.<Model_name>
.
Note: it's better to avoid importing everything from module(from <module_name> import *
)
回答3:
If you want to import only some specific module then do not use import *
.
It will take more time load your all library and so can affect the speed of your app also.
If you want to use few modules from your second app then just add module name instead of whole libraries something like this:
from app2.models import Module1, Module2
or it may be circular import issue as other clarify.
Thanks.
回答4:
You need to specify the model names you want to import, for ex from app1.models import ModelName1, ModelName2
.
回答5:
i use this code always and it's work :)
from position_app.models import Member
回答6:
Make sure there is no name clash between one of your apps and one of the modules installed in your Python environment. If you use pip, you can run pip freeze
to see a list of installed modules.
I had the same error when one of my apps was named 'packaging', and the packaging python module was installed.
回答7:
I also face this problem when I try to import my model from another app in (django2.2)
But at last I Imported It and Its successfully working.
here is my two app:
INSTALLED_APPS = [
...
'categories',
'videos',
]
and this is the code for how I Imported it into videos/models.py file as a ForeignKey Connectivity
from django.db import models
class Videos(models.Model):
categories = models.ForeignKey('categories.Categories', related_name='categories', on_delete=models.CASCADE)
If want to see my Categories Model from categories/models.py file, you can check this code otherwise neglect it
from django.db import models
class Categories(models.Model):
category_name = models.CharField(max_length=50)
created_at = models.DateTimeField(auto_now_add=True)
updated_at = models.DateTimeField(auto_now=True)
来源:https://stackoverflow.com/questions/43847173/cannot-import-models-from-another-app-in-django